A number 1/10 as great as 7962 would be 796.2
You get this answer by either dividing 7,962 with 10 which gives you 769.2
Or you can multiply 7,962 with 1/10 to get 7,962/10. If you simplify then you get 796 1/5 or 796.2.
Total Attendence = Mean Attendence × No. of Incidents
= 24,500 × 25
= 612,500.
Answer:
the last option: 
Step-by-step explanation:
Make sure you have the numerical answer for each of the functional expressions that are shown among the possible solution choices:
f(4) = -14 (what the blue function reads [its y-value] when x is 4)
g(4) = 10 (what the red function reads [its y-value] for x=4)
g(-2) = 4 (y-value of the red function when x is -2)
f(2) = -8 (y-value of the blue function for x = 2)
f(-2) = 4 (y-value of the blue function for x =-2)
use them to compare the options they give you, and the only one that matches is the last option.
There was 3000 general admission tickets sold and 500 kid ticket sold.
How did I get this?
First, we need to see what information we have.
$2.50 = General admission tickets = (G)
$0.50 = kids tickets = (K)
There were 6x as many general admission tickets sold as kids. G = 6K
We need two equations:
G = 6K
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.
2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis
15K + .50K = 7750
combine like terms
15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.
K = 7750/15.50
K = 500 tickets
So, 500 kid tickets were sold.
Plug K into our first equation (G = 6k)
G = 6*500
G = 3000 tickets
So, 3000 general admission tickets were sold,
Let's check this:
$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)
Answer:
The number of cows and calves Mitchel can transport is determined by the inequity 
Step-by-step explanation:
Let 
be the number of goats, and 
be the number of cows. If Mitchel's livestock trailer can only hold maximum of 5000 pounds. then we have the inequality
<em>(this says that the weight of the goats and the calves cannot exceed 500 pounds.) </em>
Therefore, this inequality determines the number of goats and calves Mitchel can take in a single trip.
