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velikii [3]
2 years ago
10

Sean has ordered a gift online and was told it will be delivered in a cube-

Mathematics
2 answers:
Kaylis [27]2 years ago
7 0
Math is always the answer
Svetllana [295]2 years ago
3 0

Answer:

2,400%     D

hope i helped

if i can get braibnliest that would be great

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A potato chip company makes chips to fill snack-size bags and family size bag. in one week production cannot exceed 2400 units,
Ainat [17]

Answer:

600 units of for snack-size, 1800 units for family-size

Step-by-step explanation:

7 0
2 years ago
A television is 28.5 inches wide and 16 inches long.
Umnica [9.8K]

Answer:

  33 in

Step-by-step explanation:

The Pythagorean theorem tells you ...

  diagonal² = length² +width²

  diagonal² = (16 in)² +(28.5 in)² = 1068.25 in²

  diagonal = √(1068.25 in²) ≈ 32.684 in

The diagonal of the television is about 33 inches.

7 0
2 years ago
Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi
tiny-mole [99]

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

5 0
2 years ago
Test the given claim. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, and then state the concl
never [62]

Answer:

a) Failed to reject the null hypothesis (P-value=0.09).

b) The 95% CI for the difference in proportions is:

-0.0599\leq\pi_1-\pi_2\leq0.0124

Step-by-step explanation:

a) We have to perform a hypothesis test for the difference of proportions.

The null and alternative hypothesis are:

H_0: \pi_1\geq\pi_2\\\\H_1: \pi_1

The significance level is 0.05.

The proportion of the passenger cars owners is:

p_1=\frac{239}{2142} =0.1116

The proportion of commercial truck owners is:

p_2=\frac{54}{399}=0.1353

The weigthed average p is

p=\frac{n_1p_1+n_2p_2}{n_1+n_2}=\frac{239+54}{2142+399}=0.1153

The estimated standard deviation is

s=\sqrt{\frac{p(1-p)}{n_1}+\frac{p(1-p)}{n_2}} =\sqrt{\frac{0.1153(1-0.1153)}{2142}+\frac{0.1153(1-0.1153)}{399}} =0.0174

We can calculate the z-value as:

z=\frac{\Delta p}{s}=\frac{0.1116-0.1353}{0.0174}=-1.362

The P-value for z=-1.362 is P=0.0866.

The P-value (0.09) is greater than the significance level (0.05), so it failed to reject the null hypothesis. There is no enough evidence to prove that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

b) We can construct a 95% CI, according to the significance level of 0.05.

The z-value for this CI is 1.96.

We have to recalculate the standard deviation:

\sigma=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2}} =\sqrt{\frac{0.1116(1-0.1116)}{2142} +\frac{0.1353(1-0.1353)}{399}} =0.0184

The lower limit is then:

LL=(p_1-p_2)-z*\sigma=(0.1116-0.1353)-1.96*0.0184=-0.0238-0.0361\\\\LL=-0.0599

The upper limit is:

UL=(p_1-p_2)+z*\sigma=(0.1116-0.1353)+1.96*0.0184=-0.0238+0.0361\\\\UL=0.0124

The 95% CI for the difference in proportions is:

-0.0599\leq\pi_1-\pi_2\leq0.0124

In this case, we can conclude that the difference between the proportions, with 95% confidence, can still be equal or greater than zero, meaning that it is possible passenger car owners violate laws more than truck owners.

7 0
2 years ago
X (minutes) y (bedsheets)
pickupchik [31]
Is that IXL? Anyway I think it’s 8 but I don’t think so anyway I tried don’t rely on me
5 0
2 years ago
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