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stiks02 [169]
2 years ago
10

Kaelyn has some yarn that she wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each

scarf uses 0.10.10, point, 1 kilograms of yarn. Kaelyn wants to make 333 times as many scarves as hats and use 555 kilograms of yarn.
Let hhh be the number of hats Kaelyn makes and sss be the number of scarves she makes.

Which system of equations represents this situation?

Mathematics
1 answer:
natita [175]2 years ago
7 0

Answer:A

Step-by-step explanation:

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In 2014, 85 percent of households in the United States had a computer. For a randomly selected sample of 200 households in 2014,
DochEvi [55]

Answer:

The mean of C is 170 households

The standard deviation of C, is approximately 5 households

Step-by-step explanation:

The given parameters are;

The percentage of households in the United States that had a computer in 2014 = 85%

The size of the randomly selected sample in 2014, n = 200

The random variable representing the number of households that had a computer = C

Therefore, we have;

The probability of a household having a computer P = 85/100 = 0.85

Let

Therefore;

The mean (expected) number in the sample, μₓ, = E(x) = n × P is given as follows;

μₓ = 200 × 0.85 = 170

The mean of C = μₓ = 170

The variance, σ² = n × P × (1 - P) = 200 × 0.85 × (1 - 0.85) = 25.5

Therefore;

The standard deviation, σ = √(σ²) = √(25.5) ≈ 5.05

The standard deviation of C, σ ≈ 5 households (we round (down) to the nearest whole number)

7 0
2 years ago
Read 2 more answers
Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
2 years ago
The amount of garbage, G, in tons per week, produced by a city with population p, measured in thousands of people, is given by G
ExtremeBDS [4]

Answer:

12 = f(40)

Step-by-step explanation:

From the given information:

We are being told that:

G = tons per week

p = people in thousands

However, the relation existing between the amount of garbage that is produced by a city with population p can be expressed as:

G = f(p)

Similarly, they said there exists a total population of 40000 persons in the town of Tola. i.e. 40 thousand and also 12 tons of garbage is produced by week i.e. that will be the value for G.

Then, we have:

12 = f(40)

4 0
2 years ago
A gym is considering changing its operating hours at multiple locations in a city. The gym management wants to know what percent
Marrrta [24]
You don't need the names since there is 4367, and that would only be about 1/9th of the whole amount of members, so b is out of the question. you need average people to make it, so d is out of the question, and picking a random letter out of the alphabet is as arbitrary as a, but you are adding the effect of Inconsistency so I would say Let the gym management decide which members should be surveyed is the right answer
5 0
2 years ago
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A survey of the students in Lance’s school found that 58% of the respondents want the school year lengthened, while 42% think it
alina1380 [7]
The margin of error of a given statistic is an amount that is allowed for in case of miscalculation or change of circumstances.

It is usually the radius or half of the width of the confidence interval of that statistic.

Given that a<span> survey of the students in Lance’s school found that 58% of the respondents want the school year lengthened, while 42% think it should remain the same. The margin of error of the survey is ±10%.

This means that 58% </span><span>± 10% of the </span>respondents want the school year lengthened, while 42% <span><span>± 10% think it should remain the same.</span>

Thus, from 48% to 68% </span><span><span>of the respondents want the school year lengthened, while from 32% to 52% <span>think it should remain the same.</span> </span>

Therefore, according to the survey data, at least 32% of students want the duration of the school year to remain unchanged, and at least 48% want the school year to be lengthened.</span>
7 0
2 years ago
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