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lisov135 [29]
2 years ago
8

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of

type A​ (the original​ paint) and 9 cans of type B​ (the modified​ paint) were selected and applied to similar surfaces. The drying​ times, in​ hours, were recorded. The summary statistics are as follows. Type A Type B x 1x1equals=76.3 hr x 2x2equals=65.1 hr s 1s1equals=4.5 hr s 2s2equals=5.1 hr n 1n1equals=11 n 2n2equals=9 The following​ 98% confidence interval was obtained for mu 1μ1minus−mu 2μ2​, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B. What does the confidence interval suggest about the population​ means? 4.90 hrless than
Mathematics
1 answer:
nydimaria [60]2 years ago
7 0

This question is incomplete. I got the complete part (the boldened part) of it from google as:

The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:

4.90 hrs < μ1 - μ2 < 17.50 hrs.

Answer:

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A​ (the original​ paint) and 9 cans of type B​ (the modified​ paint) were selected and applied to similar surfaces. The drying​ times, in​ hours, were recorded. The summary statistics are as follows. Type A Type B x 1x1equals=76.3 hr x 2x2equals=65.1 hr s 1s1equals=4.5 hr s 2s2equals=5.1 hr n 1n1equals=11 n 2n2equals=9 The following​ 98% confidence interval was obtained for mu 1μ1minus−mu 2μ2​, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B. What does the confidence interval suggest about the population​ means?

The mean difference for the 98% confidence interval, the drying times of the two types of paints are (4.90, 17.50). This implies that Type A paint takes between 4.90 and 17.50 hours more to dry than type B paint.

Step-by-step explanation:

The mean difference for the 98% confidence interval, the drying times of the two types of paints are (4.90, 17.50). This implies that Type A paint takes between 4.90 and 17.50 hours more to dry than type B paint.

Only positive values comprise the confidence interval which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification appears to be effective in reducing drying times.

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The dimension of a rectangular garden are 12 1/2 feet by 16 3/4 feet. If 1 5/8 feet is added to all the sides, find the new dime
Effectus [21]

Answer:

L=15\tfrac{6}{8} \ feet

B=20 \ feet

Step-by-step explanation:

Given that the dimensions of a rectangular field is (in feet)

l=12\tfrac{1}{2}=\frac{12 \times 2 +1}{2}=\frac{25}{2}

b=16\tfrac{3}{4}=\frac{16 \times 4 +3}{4}=\frac{67}{4}

Now we are being told that 1\tfrac{5}{8} feet is added to each side. Hence New Dimensions will be

1\tfrac{5}{8}=\frac{1 \times 8 +5}{8}=\frac{13}{8}

L = \frac{25}{2}+\frac{13}{8}+\frac{13}{8}

L=\frac{25 \times 4}{2 \times 4}+\frac{13}{8}+\frac{13}{8}

L=\frac{100}{8}+\frac{13}{8}+\frac{13}{8}

L= \frac{100+13+13}{8}

L= \frac{126}{8}

L=15\tfrac{6}{8}

B= \frac{67}{4}+\frac{13}{8}+\frac{13}{8}

B= \frac{67\times 2}{4\times 2}+\frac{13}{8}+\frac{13}{8}

B= \frac{134}{8}+\frac{13}{8}+\frac{13}{8}

B= \frac{134+13+13}{8}

B=\frac{160}{8}

B=20

Hence New Dimensions are

L=15\tfrac{6}{8} \ feet

B=20 \ feet

3 0
2 years ago
Read 2 more answers
Senior management of a consulting services firm is concerned about a growing decline in the firm’s weekly number of billable hou
Reil [10]

Answer:  (45.79, 51.21)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.99=0.01

Sample size : n= 51 , which is a large sample (n>30), so we use z-test.

Critical value: z_{\alpha/2}=2.576

Sample mean : \overline{x}= 48.5\text{ hours}

Standard deviation : \sigma=7.5\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 48.5\pm(2.576)\dfrac{7.5}{\sqrt{51}}

i.e.48.5\pm2.70534112234\\\\\approx48.5\pm2.71\\\\=(48.5-2.71, 48.5+2.71)=(45.79, 51.21)

Hence, 99% confidence interval for the standard deviation of the number of hours this firm’s employees spend on work-related activities in a typical week =  (45.79, 51.21)

7 0
2 years ago
Transform the equation to isolate x: ax = bx + 1. How is
shepuryov [24]

Answer:

x=\frac{1}{a-b}

The value of x is inversely proportional to the difference of <em>a</em> and <em>b</em>.

Step-by-step explanation:

The given expression is ax-bx+1

We factor the left hand side to get:

(a-b)x=1

We divide both sides by: a-b

x=\frac{1}{a-b}

Observe that the difference of a and b is in the denominator.

The whole is of the form: x\propto \frac{1}{a-b}

The value of x is inversely proportional to the difference of <em>a</em> and <em>b</em>.

6 0
2 years ago
Read 2 more answers
G(x)= -\dfrac{x^2}{4} + 7g(x)=− 4 x 2 ​ +7g, left parenthesis, x, right parenthesis, equals, minus, start fraction, x, squared,
RUDIKE [14]

Answer:

<h2>-1/2</h2>

Step-by-step explanation:

Given the function G(x)= -\dfrac{x^2}{4} + 7, the average rate of change of g(x) over the interval [-2,4], is expressed as shown below;

Rate of change of the function is expressed as g(b)-g(a)/b-a

where a - -2 and b = 4

G(4)= -\dfrac{4^2}{4} + 7\\G(4)= -\dfrac{16}{4} + 7\\G(4)= -4 + 7\\G(4) = 3\\

G(-2) = -\dfrac{(-2)^2}{4} + 7\\G(-2)= -\dfrac{4}{4} + 7\\G(-2)= -1 + 7\\G(-2)= 6

average rate of change of g(x) over the interval [-2,4] will be;

g'(x) = \frac{g(4)-g(-2)}{4-(-2)}\\ g'(x) = \frac{3-6}{6}\\\\g'(x) = -3/6\\g'(x) = -1/2

6 0
2 years ago
Adrian Beltre hit 48 home runs during the 2004 Major League Baseball season, but only hit 19 home runs in the 2005 season. By wh
aliya0001 [1]

Answer:

60.42%

Step-by-step explanation:

Number of home runs hit by Adrian Beltre in 2004 = 48

Number of home runs hit by Adrian Beltre in 2005 = 19

To find:

Percentage decrease in home run production from 2004 to 2005.

Solution:

To find the percentage decrease, first of all we need to find the decrease in the number of home runs and then we will divide with the number of home runs in 2004 and then finally will multiply the result with 100 to get the percentage decrease.

Decrease in the number of home runs = Number of home runs in 2004 - Number of home runs in 2005 = 48 - 19 = 29

\text{Percentage of decrease in Home runs} = \dfrac{\text{Decrease in home runs}}{\text{Number of home runs in 2004}}\times 100\\\Rightarrow \text{Percentage of decrease in Home runs} = \dfrac{29}{48}\times 100 \approx \bold{60.42\%}

Therefore, by 60.42% Beltre's home run production has decreased from 2004 to 2005.

4 0
2 years ago
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