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Stels [109]
1 year ago
10

Bilet ulgowy do cyrku jesto 10 zł tańszy od biletu normalnego za 3 bilety normalne i 2 ulgowe zapłacono 160 zł ile należało by z

apłacić za 2 bilety normalnei 1 bilet ulgowy
Mathematics
1 answer:
kipiarov [429]1 year ago
3 0

Answer:

Kwota zapłacona za 2 bilety normalne i 1 bilet ulgowy wynosi 98 złotych

Step-by-step explanation:

Po pierwsze, zadeklarujmy zmienne. Niech kwota zapłacona za normalne bilety wyniesie n złotych, a kwota zapłacona za bilety zniżkowe będzie d złotych

Od pierwszej części pytania powiedziano nam, że kwota za bilet ulgowy jest o 10 złotych mniejsza niż w przypadku biletu normalnego.

Stąd matematycznie n = d + 10 ......... (i)

Mówi się nam również, że kwota zapłacona za 3 normalne bilety i 2 bilety ze zniżką wynosi 160 złotych

Matematycznie można to zapisać jako;

3n + 2d = 160 .................... (ii)

Teraz, aby uzyskać kwotę zapłaconą za dwa bilety normalne i jeden bilet zniżkowy, musimy najpierw znaleźć kwotę zapłaconą za każdy bilet, korzystając z dwóch powyższych równań. Teraz zamień (i) na (ii)

mamy; 3 (d + 10) + 2d = 160

3d + 30 + 2d = 160

5d + 30 = 160

5d + 160-30

5d = 130

d = 130/5

d = 26 złotych

Kwota zapłacona za normalny bilet wynosi zatem = 26 + 10 = 36 złotych

Znajdując kwotę zapłaconą za 2 bilety normalne i 1 bilet zniżkowy, mamy 2 (36) + 26 = 72 + 26 = 98 złotych

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1 year ago
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Write an absolute value equation to satisfy the given solution set shown on a number line.
aivan3 [116]

Answer: IX - 4I ≤ 4

Step-by-step explanation:

In the numer line we can see that our possible values of x are in the range:

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And we want to find an absolute value equation such that this set is the set of possible solutions.

An example can be:

IX - 4I ≤ 4

To construct this, we first find the midpoint M of our set, in this case is 4.

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2 years ago
The linear function m=55-8.5b represents the amount m (in dollars) of money that you have after buying b books. Find the domain
Amiraneli [1.4K]

Answer:

The domain is (-∞ , ∞)

The domain is continuous

Step-by-step explanation:

Here, we want to identify the domain of the linear function

The domain in this case can be represented by the set of all real numbers.

When we talk of the domain of a function, we are simply referring to the the range of values between the smallest value on the x-axis and the largest number on the x-axis

Hence, mathematically, we are simply considering the smallest value of b up to the largest value of b in this case. Where b simply represents the number of books

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8 0
1 year ago
Colleen compared the ratios 3:8 and One-half. Her work is shown below. Write the ratios as fractions: Three-eighths and One-half
labwork [276]

This question is Incomplete

Complete Question

Colleen compared the ratios 3:8 and 1/2.

Her work is shown below.

Write the ratios as fractions: 3/8 and 1/8 Compare the numerators: 3 > 1 Write the correct statement: 3/8 > 1/2

Where did Colleen make her first mistake?

A. The common denominator should be 4 rather than 8

B. The numerators are compared incorrectly.

C. The fraction 1/2 should have been rewritten as 6/8

D. The fraction 1/2 should have been rewritten as 4/8.

Answer:

D. The fraction 1/2 should have been rewritten as 4/8.

Step-by-step explanation:

Colleen compared the ratios 3:8 and 1/2.

Step 1

Write the ratios as fractions: 3/8 and 1/2

Step 2

Compare the numerators: 3 > 1

Step 3

Compare the denominators 8 >2

Write the correct statement:

3/8 > 4/8

Therefore, D. The fraction 1/2 should have been rewritten as 4/8.

5 0
1 year ago
g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t
Evgesh-ka [11]

Answer:

Z-score 1.96

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Step-by-step explanation:

Hello!

The study variable in this case is

X: Number of people that oppose the use of photo-cop for issuing traffic tickets in a sample of 500.

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To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

p'(1-p')*1/n ⇒ then the estimated standard error is √(p'(1-p')*1/n)

The formula for the confidence interval is:

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where "Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }" represents the margin of error of the interval.

Now for a confidence level of 0.95 the value of Z is Z_{0.975}= 1.965

The estimated standard error is already calculated: \sqrt{\frac{p'(1-p')}{n} } = 0.022

The margin of error (d) is then:

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 1.965 * 0.022

d= 0.04323

I hope it helps!

7 0
1 year ago
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