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Finger [1]
2 years ago
12

The quality control department at Food Town Inc., a grocery chain in upstate New York, conducts a monthly check on the compariso

n of scanned prices to posted prices. The chart below summarizes the results of a sample of 500 items last month. Company management would like to know whether there is any relationship between error rates on regularly priced items and specially priced items.
Regular Price Advertised Special Price

Undercharge 20 10

Overcharge 15 30

Correct Price 200 225

Mathematics
1 answer:
gulaghasi [49]2 years ago
5 0

Find the attachments for step by step solutions

Note: The .01 significance level is used

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Jack bought a car for $17,500. The car loses $750 in value each year. Which equation represents the situation? Question 9 option
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If im understanding this correctly, to find the value of the car after x amount of years, the answer would be 17,500 - 750(x)
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Omar recorded the number of hours he worked each week for a year. Below is a random sample that he took from his data. 13, 17, 9
dlinn [17]
Mean =  60 / 4 = 15

13 - 15 = -2
17 - 15 =    2
9 - 15 = -6
21 - 15 = 6
Total of squares  =  4 + 4 + 36 + 36  =  80

because this is a sample we divide this by n - 1 ( = 3)

Standard deviation  =  sqrt (80/3)  = 5.16 answer




8 0
2 years ago
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The slope of a line is 2. The y-intercept of the line is -6. Which statements accurately describe how to graph the function
Law Incorporation [45]
It’s a. Start at the y intercept and rise over run to the next point.
8 0
2 years ago
An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were
vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

<u>Step:-(1)</u>

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

<u>Step :-2</u>

<u>Null hypothesis: H₀:</u> there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

<u>Alternative hypothesis :H₁: </u>there is  significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

                     Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} }  } }

Given  n₁=n₂=60.

                    Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60}  } }

On calculation, we get

                   Z =   \frac{4}{\sqrt{0.6833} }

                   z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

3 0
2 years ago
A sequence has a common ratio of Three-halves and f(5) = 81. Which explicit formula represents the sequence? f(x) = 24(Three-hal
Ede4ka [16]

Answer:

f(x)=16\, (\frac{3}{2} )^{x-1}

Step-by-step explanation:

Since we are given the common ratio (3/2), all we need to find to define the geometric sequence, is its multiplicative factor (a) that corresponds to the first term of the sequence - remember that all consecutive terms will be generated by multiplying this first value repeatedly by the common ratio (3/2) as shown below:  

f(1)=a\\f(2)=a\,*\,(\frac{3}{2} )\\f(3)=a\,*\,(\frac{3}{2} )^2\\f(4)=a\,*\,(\frac{3}{2} )^3\\f(5)=a\,*\,(\frac{3}{2} )^4

Since we are given the information that f(5)=81 we can use this to find the value of the first term:

f(5)=\,a\,*\,(\frac{3}{2} )^4\\81=\,a\,*(\frac{81}{16} )\\a\,*\,81=\,81\.*\,16\\a\,=\,16

Notice as well that the first term doesn't contain the common ratio, the second term contains the common ration (3/2) to the power one, the third one contains the common ratio to the power two, the fourth one contains it to the power three, and so forth. So the exponent at which the common ratio appears is always one unit less than the order (x) of the term in question. This concept helps us finalize the expression for the sequence's formula:

f(x)=16\,*\,(\frac{3}{2} )^{x-1}

6 0
2 years ago
Read 2 more answers
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