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sergey [27]
2 years ago
5

Igor recently immigrated to the UK. He was an experienced surgeon in his country but had to re-do his medical training in order

to work in the UK.
a) Which point on the graph represents Igor's data?

b) The managing director of this hospital concludes that the salary of a surgeon is linked to their age. Give one reason why the scatter graph might support this conclusion.

(I know that the answer is that it correlates positively but you need this for the next question to make sense.)

c) How could we make this conclusion more reliable?

Mathematics
1 answer:
jek_recluse [69]2 years ago
4 0

Answer:

a) The outlier at the bottom right of the graph

b)  The points re approximate a line with a positive slope

c) By finding the strength of the correlation, through correlation analysis

Step-by-step explanation:

a) Here we have a word problem, we are told that Igor is recently immigrated experienced but had to re-do his medical training in order to work in the UK

Therefore, he will be represented by the outlier point that is closest to the bottom right of the graph

b) The scatter graph shows that as the age of a doctor increase, the yearly salary increases proportionately

From the graph

Age      Salary

22        £28000

26        £30000

34        £44000

38        £42000

42        £30000

42        £46000

50        £55000

The point approximate a line with salary and age having a direct proportionality. that is, increasing age follows a proportionate increase in salary.

c) We can make the conclusion more reliable be carrying out a correlation analysis from which we will find the strength of the correlation between the ages and annual salaries.

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See attached image

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Answer:

The answer is below

Step-by-step explanation:

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Represent equations 1, 2 and 3 in matrix form gives:

\left[\begin{array}{ccc}1&1&1\\5.5&6&7\\-3&1&0\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}47\\302\\0\end{array}\right] \\\\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&1&1\\5.5&6&7\\-3&1&0\end{array}\right] ^{-1} \left[\begin{array}{c}47\\302\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}6\\18\\23\end{array}\right]

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