Aluminium cylinder: m = 12.4 g, L = 2.00 cm.
V = π r² L
Density of the aluminium: 2.7 g / cm³
V = 12.4 g : 2.7 g/cm³ ≈ 5 cm³
5 = 3.14 · r² · 2
r² = 5 : 6.28
r² = 0.796
r = √0.796
r = 0.9 cm
Answer:
The radius of an aluminium cylinder is 0.9 cm.
Answer:
pls follow me not because I am genius but because I am a swager SWAG
Step-by-step explanation:
by swag
Answer:
9
Step-by-step explanation:
Okay, here we have a table with the x and y columns
What we are to find is F(3)
Now this is obtainable from the table
The term f(x) equals values in the table y
We can obtain the values of y from the equation linking x to y
Now the term f(3) can be obtained by checking the value of y or f(x) that corresponds to the value 3
We can see that it is the last term on the x side that can give the value of y we are looking for
So without much further ado we can see that it is the last value on the table y we are also looking at
This equals 9
So F(3) = 9
15x = 45
x = 3
10z = 45
z = 4.5
m<1 = 4y - 18
90 = 4y - 18
4y = 90 + 18
4y = 108
y = 27
Answer: The number of different combinations of 2 vegetables are possible = 15 .
Step-by-step explanation:
In Mathematics , the number of combinations of selecting r values out of n values = 
Given : Number of available vegetables = 6
Then, the number of different combinations of 2 vegetables are possible will be :
Hence , the number of different combinations of 2 vegetables are possible = 15 .
