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Rudik [331]
2 years ago
15

A _____ is an electronic path over which data can travel.

Computers and Technology
1 answer:
vazorg [7]2 years ago
5 0
A bus is an electrical path which data travels between the different components in an electronic device.                                                                      
You might be interested in
Return 1 if ptr points to an element within the specified intArray, 0 otherwise.
Paladinen [302]

Answer:

int withinArray(int * intArray, int size, int * ptr) {

      if(ptr == NULL) // if ptr == NULL return 0

            return 0;

      // if end of intArr is reached

      if(size == 0)

          return 0; // element not found

  else  

          {

            if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr

                   return 1; // return 1

            return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements

         }

}

Explanation:

Above is the completion of the program.

4 0
2 years ago
In which of the following stages of the development process is a team MOST likely to interview a potential user of an app?
Sedaia [141]

Answer:

Its c

Explanation:

5 0
2 years ago
The processing speed of a microprocessor is typically represented by its _______.
Fiesta28 [93]
<span>Correct Answer:
A. FireWire</span>
8 0
2 years ago
Which two factors most influenced the growth of the Internet during the 1970s?
eduard

Answer:

The answer is "increase in the power of public universities and increased appreciation for a liberal arts education". DARPA and Russia had nothing to do with this. Yes, the computer hardware improvement led to a growth, but National Science Foundation funding in 1981, and hence this is also not an option. And electrical power supply had nothing to do with this. Hence, the above answer. as the concept of the internet is based on liberal arts of education, to impart practical and intellectual skillsets, and hence to grow the social responsibility among the citizens of the whole world. Also, the power of public universities had a big role to play definitely, and this was confirmed from Pentagon as well then when the question was raised, is this due to the risk of a nuclear attack.

Many people think that the main reason was the nuclear attack threat, but that was not an issue definitely. Actually this was the time of liberalization, and the power of the public universities was increased. Hence, they got the chance to share the information of various sorts with the people, and in the process internet started expanding.

Explanation:

The answer is self explanatory.

8 0
2 years ago
Read 2 more answers
The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a
Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0
2 years ago
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