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Ahat [919]
2 years ago
3

Meg lives in Indianapolis and wants to visit her mom in lima. How many more kilometers would meg drive if she drove to lima thro

ugh dayton?
Mathematics
2 answers:
White raven [17]2 years ago
6 0
It should be 44 miles
muminat2 years ago
4 0

Answer:

44

Step-by-step explanation:

I did it on khan

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Identify the parameter n in the following binomial distribution scenario. A basketball player has a 0.479 probability of
lozanna [386]

Answer:

n = 17

Step-by-step explanation:

Assuming

- probability of success (making free throw) does not vary

We have

n = 17 (trials)

p = 0.479

x > 9

7 0
2 years ago
Change 21 out of 71 to a percentage. Give your answer to 1 decimal place
melisa1 [442]
1. 29.6%
2. 18.1%
3. 27.9%
4. 75.4%
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2 years ago
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Martin's car had 86,456 miles on it. Of that distance, Martin's wife drove 24,901 miles,
navik [9.2K]

Answer:

Martin drove 53,558 miles.

Step-by-step explanation:

If you add up the amount of miles his son and wife drove, you get 32,898. To get the answer, you would subtract that from the total number of miles to get 53,558.

3 0
2 years ago
Fatima Sheroud sells children’s clothing for The Grasshopper Shoppe. She is paid weekly on a straight commission of 4% on sales
Minchanka [31]

Answer:

7890

Step-by-step explanation:

(5000*4%)+(x*5%)=594.50

200+(x*5%)=594.50

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3 0
2 years ago
The time for a visitor to read health instructions on a Web site is approximately normally distributed with a mean of 10 minutes
klio [65]

Answer:

a) The mean is 10 and the variance is 0.0625.

b) 0.6826 = 68.26% probability that the mean time of the visitors is within 15 seconds of 10 minutes.

c) 10.58 minutes.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Normally distributed with a mean of 10 minutes and a standard deviation of 2 minutes.

This means that \mu = 10, \sigma = 2

Suppose 64 visitors independently view the site.

This means that n = 64,  = \frac{2}{\sqrt{64}} = 0.25

a. The expected value and the variance of the mean time of the visitors.

Using the Central Limit Theorem, mean of 10 and variance of (0.25)^2 = 0.0625.

b. The probability that the mean time of the visitors is within 15 seconds of 10 minutes.

15 seconds = 15/60 = 0.25 minutes, so between 9.75 and 10.25 seconds, which is the p-value of Z when X = 10.25 subtracted by the p-value of Z when X = 9.75.

X = 10.25

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{10.25 - 10}{0.25}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 9.75

Z = \frac{X - \mu}{s}

Z = \frac{9.75 - 10}{0.25}

Z = -1

Z = -1 has a p-value of 0.1587.

0.8413 - 0.1587 = 0.6826.

0.6826 = 68.26% probability that the mean time of the visitors is within 15 seconds of 10 minutes.

c. The value exceeded by the mean time of the visitors with probability 0.01.

The 100 - 1 = 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

Z = \frac{X - \mu}{s}

2.327 = \frac{X - 10}{0.25}

X - 10 = 2.327*0.25

X = 10.58

So 10.58 minutes.

6 0
2 years ago
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