With the sum of 99, we will get 50 pairs whole numbers. Why?
Let’s start with
0+ 99
1 + 98
2 + 97
3 + 96
4 + 95
5 + 94
6 + 93
7 + 92
8 + 91
9 + 90
10 + 89
………
……..
43 + 49
44 + 50
Therefore, if you’re going to count all pairs of whole number, you will get 50 pairs of whole number with the sum of 99.
Hope this helps!
For this case, what you should know is that Sue Jones insurance covers half of the expenses. Equivalently, her insurance covers:
10/20 = 1/2 = 0.5
Therefore, we have then that
a. for Albert
0.5 * (12000) = $ 6000
b. for Sam
0.5 * (8000) = $ 4000
c. total
The sum of the results of parts a and b
$ 6000 + $ 4000 = $ 10,000
answer
$ 6000
$ 4000
$ 10,000
Answer:
Becky, because her reason I'm step 2 does not justify her 2ndbstatement.
Step-by-step explanation:
Two angles which add up to give 180° are said to be defined as supplementary angles.
The Definition of Supplementary Angles is the most appropriate statement to justify the second statement in the proof, as written by Angie, compared to the Angle Addition Postulate stated by Becky.
The Angle Addition Postulate does not justify why the two of angles both equal 180°. According to the Angle Anldditiin Postulate, sum of 2 angles that share the same side can does not necessarily have to be 180°. It could be less than or greater than 180°.
Therefore, Becky completed her proof incorrectly.
Answer:
The set of numbers of the form 
, q≠0 and q≠ 1 or -1.
Step-by-step explanation:
We have that,
U = the universal set = the set of all rational numbers
S = set of all integers.
It is required to find 
.
Now, is the complement of the set S.
i.e. = U - S = set if rational numbers - set of integers
i.e. = the set of rationals which are not integers i.e. the set of points of the form , q≠0 and q≠ 1 or -1.
Answer:
Critical value t-score=2.701.
Step-by-step explanation:
When we calculate a confidence interval with an unknown population standard deviation, we estimate it from the sample standard deviation and use the t-score instead of the z-score.
The critical value for t depends on the level of confidence and the degrees of freedom.
If the sample size is 42, the degrees of freedom are:
For a confidence level of 99% and 41 degrees of freedom, the critical value of t is t=2.701.
