Answer: The function that modes this situation would be: y = 475(1 + .0125)^x.
This is an example of an exponential equation. These equations are always in the form y = ab^x.
The a value is the starting value. The b value is the interest rate. The x value is the number of years.
The only thing to be careful about is the rate. We are adding 1.25% or 0.125. Make sure that you are adding 1 whole to the 1.25% and don't just use 0.125.
Answer:
1,778
Step-by-step explanation:
Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.
Truck A's cost for 10 years is ...
A = C+600 +(0.06)(2.25)(10X) -(S+200)
Truck B's cost for 10 years is ...
B = C +(0.07)(2.25)(10X) -S
We want to find X such that Truck A's cost is lower, so ...
C -S +1.35X +400 < C -S +1.575X
400 < 0.225X
1777 7/9 < X
1778 miles driven per year (or more) makes Truck A a better option.
<h3>Answer:</h3>
x = -2
<h3>Explanation:</h3>
The line represents the output value (y) for a given input value (x). Where the lines cross, the output values are equal. These lines cross at x=-2.
Answer:
a) 0.00019923%
b) 47.28%
Step-by-step explanation:
a) To find the probability of all sockets in the sample being defective, we can do the following:
The first socket will be in a group where 5 of the 38 sockets are defective, so the probability is 5/38
The second socket will be in a group where 4 of the 37 sockets are defective, as the first one picked is already defective, so the probability is 4/37
Expanding this, we have that the probability of having all 5 sockets defective is: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%
b) Following the same logic of (a), the first socket have a chance of 33/38 of not being defective, as we will pick it from a group where 33 of the 38 sockets are not defective. The second socket will have a chance of 32/37, and so on.
The probability will be (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%
Answer:
c
Step-by-step explanation:
