I'm going to assume that you meant 450kg for the combined weight, 190kg more and 3 Llamas. I'm pretty sure Llamas and Okapis don't weigh 450450450kg (that's 993,073,252 pounds). :)
x= Okapi weight
y= Llama weight
EQUATIONS:
There are 2 equations to be written:
1) 450kg is equal to the weight of one Okapi and one Llama
450kg= x + y
2) The weight of 3 llamas is equal to the weight of one Okapi plus 190kg.
3y=190kg + x
STEP 1:
Solve for one variable in one equation and substitute the answer in the other equation.
450kg= x + y
Subtract y from both sides
450-y =x
STEP 2:
Substitute (450-y) in second equation in place of x to solve for y.
3y=190kg + x
3y=190 + (450-y)
3y=640 -y
add y to both sides
4y=640
divide both sides by 4
y=160kg Llama weight
STEP 3:
Substitute 160kg in either equation to solve for x.
3y=190kg + x
3(160)=190 + x
480=190 + x
Subtract both sides by 190
290= x
x= 290kg Okapi weight
CHECK:
3y=190kg + x
3(160)=190 + 290
480=480
Hope this helps! :)
Answer:
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
Step-by-step explanation:
Consider the provided information.
The mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is 0.58.
Mean = μ= 12.5
σ = 0.58
n = 15
![\mu\pm2\sigma=12.5\pm 2(0.58)\\\mu\pm2\sigma=12.5\pm1.16\\\mu\pm2\sigma=[11.34, 13.66]](https://tex.z-dn.net/?f=%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm%202%280.58%29%5C%5C%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm1.16%5C%5C%5Cmu%5Cpm2%5Csigma%3D%5B11.34%2C%2013.66%5D)
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
Let us see... ideally we would like to have all equations with the same exponent or the same base so that we can compare the rates. Since the unknown is in the exponent, we have to work with them. In general,
![x^(y/z)= \sqrt[z]{x^y}](https://tex.z-dn.net/?f=x%5E%28y%2Fz%29%3D%20%5Csqrt%5Bz%5D%7Bx%5Ey%7D%20)
.
Applying this to the exponential parts of the functions, we have that the first equation is equal to:
250*(
![\sqrt[5]{1.45} ^t](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B1.45%7D%20%5Et)
)=250*(1.077)^t
The second equation is equal to: 200* (1.064)^t in a similar way.
We have that the base of the first equation is higher, thus the rate of growth is faster in the first case; Choice B is correct.
you don't list the choices but you would divide the total dollar amount by 5 to find out the number of bills there are so it should be something like :
total bills = x/5