Question

Calculate the moles of camphor dissolved in 1.32 L of phenol. The molar mass of camphor is 152 g/mol and the molarity of phenol solution is 6.01 M.

Answer 1

Answer:

moles of camphor = 0.0522 moles

Explanation:

Data:

MW camphor= 152 g/mol

V solution = 1.32 L

M solution = 6.01 M

moles solute = ?

• To calculate the moles of camphor, you must first know the grams of solute (camphor) that exist in the solution, this is calculated from the molarity equation:

$M=\frac{solute mass}{solution volume}$

• From there the grams of the solute (camphor) are cleared:

$solutemass=M*solutionvolume=6.01M*1.32L=7.9332g$

• Then by means of the molecular weight (MW) equation the moles can be obtained:

$MW=\frac{mass}{moles}$

$moles=\frac{mass}{MW} =\frac{7.9332g}{152\frac{g}{mol} } =0.0522 moles$