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OverLord2011 [107]
2 years ago
9

An arena receives $1,700 per event for 12 concerts. If the costs for this sponsorship total $14,000, what is the profit margin f

or the concert sponsorship?
Mathematics
1 answer:
Jobisdone [24]2 years ago
6 0

Answer:

The profit margin for the concert sponsorship is 31.3725 %

Step-by-step explanation:

An arena receives for 1 event = $1700

An arena receives for 12 events = 12 \times 1700

An arena receives for 12 events = 20400

The costs for this sponsorship total $14,000

Profit = 20400-14000

Profit =6400

Profit margin =\frac{6400}{20400} \times 100

Profit margin = 31.3725\%

Hence the profit margin for the concert sponsorship is 31.3725 %

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--------------------   = ----------------

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It costs $23 per hour plus a flat fee of $16 for a plumber to make a house call. What is the equation of the form y = mx + b for
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serious [3.7K]

Answer:

(a) The probability that during the next hour less than 3 patients will be admitted is 0.00623.

(b) The probability that during the next two hours exactly 8 patients will be admitted is 0.00416.

Step-by-step explanation:

<u>The complete question is:</u> General Hospital has noted that they admit an average of 8 patients per hour.

(a) What is the probability that during the next hour less than 3 patients will be admitted?

(b) What is the probability that during the next two hours exactly 8 patients will be admitted?

The above situation can be represented through Poisson distribution as it includes the arrival rate of the pattern. So, the probability distribution of the Poisson distribution is given by;

P(X = x) = \frac{e^{-\lambda} \times \lambda^{x} }{x!} ; x = 0,1,2,......

Here X = Number of patients admitted in the hospital

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So, X ~ Poisson(\lambda = 9)

(a) The probability that during the next hour less than 3 patients will be admitted is given by = P(X < 3)

    P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

                  = \frac{e^{-9} \times 9^{0} }{0!} + \frac{e^{-9} \times 9^{1} }{1!} + \frac{e^{-9} \times 9^{2} }{2!}

                  = e^{-9}  +(e^{-9} \times 9)+ \frac{e^{-9} \times 81}{2}

                  = <u>0.00623</u>

(b) Here, \lambda = 9 \times 2 = 18 because we have to find the probability for the next two hours and we are given in the question of per hour.

So, X ~ Poisson(\lambda = 18)

Now, the probability that during the next two hours exactly 8 patients will be admitted is given by = P(X = 8)

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3 0
2 years ago
Is it possible for an odd function to have the interval 0 infinity) as its domain?
mojhsa [17]

NO!

Prove by contradiction. First, define the the following terms:

odd function: f(-x) = -f(x)] and domain: all values of x

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Answer: No

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