In ΔPQR, the measure of ∠R=90°, QR = 8 feet, and RP = 3.9 feet. Find the measure of ∠P to the nearest degree.
1 answer:
Answer:
64°
Step-by-step explanation:
Check the attachment for the diagram. Since the triangle has one of its angle as 90°, it is a right angled triangle.
Using the SOH CAH TOA trigonometry ratios:
Since ∠P is opposite to side QR,
QR = opposite side = 8ft
RP = adjacent side = 3.9ft
According to TOA
Tan∠P = Opposite/Adjacent = QR/RP
Tan∠P = 8/3.9
Tan∠P = 2.05
∠P = arctan 2.051
∠P = 64°
You might be interested in
Answer: Last option.
Step-by-step explanation:
Observe the base of the pyramid, which is a regular hexagon. You can see that there is a right triangle.
The area of the triangle can be calculated with this formula:
Where "b" is the base and "h" is the height.
You can say that the apothem is the height of the right triangle, then, you need to find the base applying the Pythagorean Theorem:
Then, the area of the triangle is:
Since the base of the pyramid is a regular hexagon, then you can multiply by 12 the area of the right triangle calculated above, in order to find the area of the hexagon. Then you get:
Assuming all of them had the same amount at the start
