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2 years ago

11

Four students are determining the probability of flipping a coin and it landing head's up. Each flips a coin the number of times

shown in the table below.
Student
Number of Flips
Ana
50
Brady
10
Collin
80
Deshawn
20

Which student is most likely to find that the actual number of times his or her coin lands heads up most closely matches the predicted number of heads-up landings?
Ana
Brady
Collin
Deshawn

2 answers:

Oxana [17]2 years ago

7 0

Answer:

Collin

Step-by-step explanation:

He did the most attempts.

The probability of flipping a coin is 1/2

kozerog [31]2 years ago

4 0

Answer:

The answer would be Collin

Step-by-step explanation:

Four students are determining the probability of flipping a coin and it landing head's up. Each flips a coin the number of times shown in the table below.

Ana

50

Brady

10

Collin

80

Deshawn

20

So the answer would be collin

Edg : )

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The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − (x − π/2) + 1/6 (x − π/2)3 + R3(x). Usin

Otrada [13]

Answer:

The cosine of 86º is approximately 0.06976.

Step-by-step explanation:

The third degree Taylor polynomial for the cosine function centered at $a = \frac{\pi}{2}$ is:

$\cos x \approx -\left(x-\frac{\pi}{2} \right)+\frac{1}{6}\cdot \left(x-\frac{\pi}{2} \right)^{3}$

The value of 86º in radians is:

$86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi$

$86^{\circ} = \frac{43}{90}\pi\,rad$

Then, the cosine of 86º is:

$\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}$

$\cos 86^{\circ} \approx 0.06976$

The cosine of 86º is approximately 0.06976.

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2 years ago

Chloe collected 4 times as many bags of cans as her friend. If her friend collected 1/6 of a bag, how much did Chloe collect?

dalvyx [7]

2/3 of a bag might be the anwser

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2 years ago

If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs

sammy [17]

Answer:

$QS=68\ units$

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

so

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

$8x-43=(2x-4)+(4x-1)$

$8x-43=6x-5$

$8x-6x=43-5$

$2x=38$

$x=19$

step 2

Find the value of RS

$RS=2x-4$

substitute the value of x

$RS=2(19)-4$

$RS=34\ units$

step 3

Find the value of QS

Remember equation A

QS=2RS

so

$QS=2(34)=68\ units$

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2 years ago

Which shows the correct first step to solving the system of equations in the most efficient manner? 3 x + 2 y = 17. x + 4 y = 19

skelet666 [1.2K]

Answer: First option.

Step-by-step explanation:

<h3> The missing picture is attached.</h3><h3></h3>

You can use these methods to solve a System of Equations and find the value of the variables:

A. Substitution method.

B. Elimination method.

In this case, given the following System of equations:

$\left \{ {{3 x + 2 y = 17} \atop {x + 4 y = 19}} \right.$

The most efficient method to solve it is the Substitution Method. The procedure is:

Step 1: Solve for one of the variables from the most convenient equation.

Step 2: Make the substitution into the other equation and solve for the other variable in order to find its value.

Step 3: Substitute the value obtained into the equation from Step 1 and evaluate, in order to find the value of the other variable.

Based on this, you can identify that first step to solve the given System of equations, is solving for "x" from the second equation:

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3 0

2 years ago

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The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 lo

butalik [34]

Answer:

The approximate loudness of a rock concert with a sound intensity of $10^{-1}$ is 110 Db.

Step-by-step explanation:

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is : $L=10 log (\frac{I}{I_0})$

$I_0=10^{-12}$

We are supposed to find What is the approximate loudness of a rock concert with a sound intensity of $10^{-1}$

So, $I = 10^{-1}$

Substitute the values in the formula :

$L=10 log (\frac{10^{-1}}{10^{-12}})$

$L=10 log (10^{11})$

L=110 Db

So, the approximate loudness of a rock concert with a sound intensity of $10^{-1}$ is 110 Db.

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2 years ago

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