Question

A total of 600 advertisements were sold for a certain magazine. If 30 percent of the first 200 sold were in color, 20 percent of the next 300 sold were in color, and 90 percent of the last 100 sold were in color, what percent of the 600 advertisements were in color? WILL PICK BRANILIEST

Answer 1

Answer:

35%

Step-by-step explanation:

Total no of advertisement = 600

Percentage advertisement out of first 200 in color = 30%

30% of 200 = 30/100 * 200 = 60

Therefore out of first 200,   60 are in color.

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Percentage advertisement out of next 300 in color = 20%

20% of 300 = 20/100 * 300 = 60

Therefore out of next 200,   60 are in color.

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Percentage advertisement out of last 100 in color = 90%

90% of 100 = 90/100 * 100 = 90

Therefore out of last 100,   90 are in color.

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Total colored advertisement will be sum of 60, 60, 90 advertisement out of first , second and third set of advertisement sold.

which is  = 60 + 60 + 90 = 210.

Therefore 210 out of total 600 advertisements sold were in color.

percentage of colored advertisements out of total advertisements will

= (colored advertisements/total advertisements )*  100

substituting the value of colored advertisements sold(210)  and total advertisements (600 ) in above expression we have

percentage of colored advertisements out of total advertisements will

= (210/600 )*  100 = 35%

Hence , 35% of the 600 advertisements were in color