Answer:
Here we have given two catogaries as degree holder and non degree holder.
So here we have to test the hypothesis that,
H0 : p1 = p2 Vs H1 : p1 not= p2
where p1 is population proportion of degree holder.
p2 is population proportion of non degree holder.
Assume alpha = level of significance = 5% = 0.05
The test is two tailed.
Here test statistic follows standard normal distribution.
The test statistic is,
Z = (p1^ - p2^) / SE
where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]
p1^ = x1/n1
p2^ = x2/n2
p^ = (x1+x2) / (n1+n2)
This we can done in TI_83 calculator.
steps :
STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER
Test statistic Z = 1.60
P-value = 0.1090
P-value > alpha
Fail to reject H0 or accept H0 at 5% level of significance.
Conclusion : There is not sufficient evidence to say that the percent of correct answers is significantly different between degree holders and non-degree holders.
Answer:
10
Step-by-step explanation:
"When 9 is increased by 3x"
THis means 9 + 3x
"The result is greater than 36"
We use greater than sign and 36
So we can write:
9 + 3x > 36
SOlving this via equation rules and algebra:
9 + 3x > 36
3x > 36 - 9
3x > 27
x > 27/3
x > 9
This means x is everything greater than 9, which satisfies the equation. So in terms of integers, it can be 10, 11, 12, 13...anything above
We want to find the least possible integer value of x, so it is definitely 10
Answer:
Step-by-step explanation: The student divided the number of wins by the number of losses.
The student should have divided the number of wins by the total number of games.
The student should have first added 20 and 10 to find that there were a total of 30 games.
Answer:
(a) After 5 years what will be his age?
"5 + y" years old
(b) What was his age 6 years back?
"y - 6" years old
(c) His grandfather‘s age is 5 times his age, What is the age of grandfather?
"5y" years old
(d) His father’s age is 6 years more than 3 times his age. What is his father’s age?
"6 + 3y" years old
Note: Ignore the quotation marks, ""
