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dangina [55]
2 years ago
8

The number of basketball jerseys sold (Y) during certain months (x) at

Mathematics
1 answer:
Klio2033 [76]2 years ago
6 0

Answer:

March (3) to December (12)

Step-by-step explanation:

Given:

The graph above

Required:

Months where the number of Jerseys sold at least 150?

The above graph is a typical two dimensional graph.

A 2 dimensional graph has x and y axis.

The y axis (vertical) of this graph holds the number of jersey sold

While the x axis (horizontal) of this graph holds the number of month.

To check the month where at least 150 jerseys were sold, we mark the "150 mark" on the y axis then we trace it to the x axis.

For convenience sake, we'll make use of a line (see attachment).

Every month that falls under this line will not regarded as sales less than 150 (meaning that these months do not count as part of the answer)

From the line on the attachment, only the 3rd month to the 12th month satisfy this criteria.

Hence, the months at which number of sold jersey was atleast 150 is 3 to 12.

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Jane builds a ramp made of a triangular prism and a rectangular prism. What is the volume
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Answer:

Correct option: third one ->  11.5 m3

Step-by-step explanation:

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Now, to find the volume of the ramp, we just need to sum both volumes:

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Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a differen
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Answer:

5 miles.

Step-by-step explanation:

Consider the question: Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a different route taking 2 1/2 hours. How many miles did Jinghua hike on the return trip ?

First of all, we will find Jinghua's speed using given information as:

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Convert mixed fractions into improper fractions:

4\frac{1}{2}\Rightarrow \frac{9}{2}

2\frac{1}{4}\Rightarrow \frac{9}{4}

\text{Jinghua's speed}=\frac{\frac{9}{2}\text{ Miles}}{\frac{9}{4}\text{ Hours}}

Using property \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}:

\text{Jinghua's speed}=\frac{9*4\text{ Miles}}{9*2\text{ Hours}}

\text{Jinghua's speed}=\frac{2\text{ Miles}}{\text{ Hour}}

We know that distance is equal to the product of speed and time.

\text{Distance}=\text{Speed}\times\text{Time}

Since we have been given that Jingua hiked the return trip at the same average rate, so distance covered by her on return trip would be speed (2 miles her hour) times given time (2 1/2 hours).

\text{Distance covered by Jingua on return trip}=\frac{2\text{ Miles}}{\text{ Hour}}\times 2\frac{1}{2}\text{ Hours}

\text{Distance covered by Jingua on return trip}=2\text{ Miles}\times \frac{5}{2}

\text{Distance covered by Jingua on return trip}=5\text{ Miles}

Therefore, Jingua hiked 5 miles on her return trip.

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