Answer:
Check the explanation
Explanation:
Given
1) CU traixial compression test
2) Devatoric stress at failure = бd = 50 kN/
3) Confining pressure at failure = бd = 48 kN/
4) Pore pressure at failure = u = 18 kN/
5) Unconfined compression stress = q = 20 kN/
6) Undrained cohesion = q/2 = 20 kN/
To find:
1) Effective and total stress strength failure envelope
Kindly check the attached image below .
Answer:
new boiler total cost = $229706.825
new boiler total cost = $127512
Explanation:
given data
power p1 = 80 kW
cost C = $160000
cost index CI 1 = 187
cost index CI 2= 194
cost capacity factor f = 0.6
power p2 = 120 kW
current cost = $18000
to find out
total cost and cost of 40 kW
solution
we consider here CN cost for new boiler and CO cost for old boiler
and x is capacity of new boiler
first we find old boiler current cost that is
current cost CO = C × .............1
put here value
current cost = 160000 ×
new current cost = $165989.304
and
use here power sizing technique for 124 kW
CN/CO = ...............2
put here value and find CN
CN/CO =
CN / 165989.304 =
CN = 211706.825
so new cost = $211706.825
so
total cost for new boiler is
total cost = new cost + current cost
total cost = 211706.825 + 18000
new boiler total cost = $229706.825
and
for 40 kW new cost will be
use equation 2
CN/CO =
CN / 165989.304 =
CN = 109512
so new cost is $109512
so
total cost for new boiler is
total cost = new cost + current cost
total cost = 109512 + 18000
new boiler total cost = $127512
Answer:
(A) Power output will be 5.55 KW (b) lower temperature will be 315 K
Explanation:
We have given efficiency of heat engine = 0.37
Input power = 15 KW
Temperature of heat reservoir
(A) We know that
So [text]0.37=\frac{output}{15}[text]
Output = 5.55 KW
(B) We also know that [text]\eta =1-\frac{T_L}{T_H}0.37=\frac{output}{15}[text], here is lower temperature and
is higher temperature
So
