Answer:
ai) n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) see attachment
bi) n(C⋂G) = x = 1
bii) n(G) only = 3
Step-by-step explanation:
Let chemistry = C
Economic = E
Government = G
n(E) = 12
n(G) = 8
n(C) = 7
ai) number of pupils for economics and chemistry = 0
number of pupils for economics and government = 4
The set notation for both:
n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) find attached the Venn diagram
bi) n(C⋂G) = ?
Let number of n(C⋂G) = x
From the Venn diagram
n(C) only = 12-4 = 8
n(G) only = 8-(4+x) = 4-x
n(E) only = 7-x
n(E⋂C⋂G) = 0
n(E⋂C) = 0
n(E⋂G) = 4
Total: 8+ 4-x + 7-x + x + 0+0+4 = 22
23 -x = 22
23-22 = x
x = 1
n(C⋂G) = x = 1
Number of pupils that take both chemistry and government = 1
(bii) government only = n(G) only = 4-x
n(G) only = 4-1 = 3
Number of students that take government only = 3
Answer:
Option D.
Step-by-step explanation:
In the given graph x-axis represents the number of owners and y-axis represents yearly cost of pets, in hundreds.
It is given that the graph passes through the points (1,15), (3,7) and (10,0).
We need to check whether (4.5, 6) is a realistic solution for the function or not. (4.5,6) point represents
Number of owners = 4.5
yearly cost of pets = 6
It is realistic that owners spend $600 a year on their pet(s).
Number of owners can not be a fraction value. So, it is not realistic to have 4.5 owners.
Therefore, the correct option is D.
Just so u know, ur output value is f(x) and ur input value is x
f(x) = -2x^2 - 3x + 5....when ur input value(x) is -3
f(-3) = -2(-3^2) - 3(-3) + 5 =
f(-3) = -2(9) + 9 + 5
f(-3) = -18 + 14
f(-3) = -4 <==
Answer:
The area of the sumo wrestling ring is 
Step-by-step explanation:
The circumference of the circular sumo wrestling ring is 
, that means its radius 
is:
Now once we have the radius of the sumo wrestling ring we can find its area 
by the following formula:
Putting in the value of 
we get:
Therefore the area of the sumo wrestling ring is 
Answer:
Step-by-step explanation:
