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arlik [135]
1 year ago
13

Which numbers are irrational? Check all that apply.

Mathematics
2 answers:
SVETLANKA909090 [29]1 year ago
6 0

Answer:

D, E, F are correct

Step-by-step explanation:

I know this because the square root of 196 is 14, the square root of 80 is 8.94427191 and if you square that you'll get 80. The square root of 16 is 4. So that is why A, B, C are wrong because they are all rational. Pi is infinite so it is irrational, the square root of 12 cannot be multiplied by itself to make 12 so it is irrational, and 7 divided by 18 is 3.8 and the 8 goes on for infinity.

Vitek1552 [10]1 year ago
5 0

Answer:

B,D,E

Step-by-step explanation:

this are the CORRECT Answer!

Pls BRAINLIEST

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There is an 8.38% probability that the anchor will be fired.

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For each resident, there is only two possible outcomes. Either they can name the news anchor on the evening news at their station, or they cannot.

This means that the binomial probability distribution will be used in our solution.

However, we are working with samples that are considerably big. So i am going to aaproximate this binomial distribution to the normal.

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

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400 city residents are going to be asked. So n = 400.

Suppose that in fact 12% of city residents could name the anchor if asked. This means that p = 0.12.

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\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{400*0.12*0.88} = 6.5.

They plan to fire the news anchor if fewer than 10% of the residents in the sample can do so.

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10% of the residents is 0.10*400 = 40 residents.

Fewer than 10% is 39 residents. So the probability that the anchor will be fired is the pvalue of Z when X = 39.

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Z = \frac{X - \mu}{\sigma}

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Z = -1.38

Z = -1.38 has a pvalue of 0.0838. This means that there is an 8.38% probability that the anchor will be fired.

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