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trapecia [35]
2 years ago
7

Sharon has some one-dollar bills and some five-dollar bills. She has 14 bills. The value of the bills is $30. Solve a system of

equations using elimination to find how many of each kind of bill she has.
a. 3 five-dollar bills, 15 one-dollar bills

b. 5 five-dollar bills, 5 one-dollar bills

c. 5 five-dollar bills, 9 one-dollar bills

d. 4 five-dollar bills, 10 one-dollar bills
Mathematics
1 answer:
Ludmilka [50]2 years ago
3 0

Answer:

d

Step-by-step explanation:

5x4 = 20 + 10 = 30 and it cant be a or b because they have too many bills and c doesnt have the right amount of money

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Find FL if H is the circumcenter of EFG,
Zanzabum

The artistic crop isn't helpful; it cuts off some vertex names.

The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn.  We have right triangle ELH, right angle L, so

EH² = HL² + EL²

EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339

Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.

Answer: 4.25

8 0
2 years ago
What percent of 137.4 is 96?
Neporo4naja [7]
X = 96

100 137.4

137.4x=(100)(96)

137.4x=9600

137.4x/137.4=9600/137.4

x=70%
7 0
2 years ago
Glenna wants to rent a car for a trip to key west for one weekshe calls two car rental companies to get prices. mr kotters renta
Korvikt [17]

Answer: Barbarino's rentals has a better deal.

She has to drive 887.5 miles to spend the same amount at either company.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

<em>Mr.kotters rentals (A) </em>

  • <em>$99 PER WEEK </em>
  • <em>$0.11per mile over 100 miles </em>

<em>Barbarino's rentals (B) </em>

  • <em>$75 per week </em>
  • <em>$0.15 per mile over 150 miles </em>

For "A"

Cost = 0.11 (432-100) + 99 = $135.52

For "B"

Cost= 0.15 (432-150) +75 = $117.3

Barbarino's rentals has a better deal, since $117.3(B) < $135.52 (A)

To find how many miles would Glenna drive before she would be spending the same amount at either company:

A =B

0.11 (M-100) + 99 =0.15 (M-150) +75 = $117.3

Solving for M (miles)

0.11 M -11+99 = 0.15 M -22.5+75

-11 +99 +22.5 -75 =0.15M -0.11 M

35.5 = 0.04M

35.5/0.04 = M

887.5 =M

She has to drive 887.5 miles to spend the same amount at either company.

4 0
2 years ago
Margaret took a trip to Italy. She had to convert US dollars to euros to pay for her expenses there. At the time she was traveli
creativ13 [48]
The conversion rate US dollars to Euros is represented with the function:
E(n)=0.72n
n- number of dollars
E(n) - Euros as a function of US dollars

The conversion rate Euros to Dirhams is :
D(x)=5.10x
x- number of Euros
D(x)- Dirhams as a function of Euros

<span>We are trying to find D(x) in terms of n.
D(x) = 5.10x
x can be rewritten as E(n)
D(x) = 5.10(E(n))
D(x) = 5.10(E(n))
D(x) = 5.10(0.72n)
D(x) = 3.672n </span>

According to this the following statement is true:
A) <span>(D x E)(n) = 5.10(0.72n)</span>
8 0
2 years ago
injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and ri
diamong [38]

Answer:

The length of the track is approximately 51.7 ft

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle.

5 0
2 years ago
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