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tia_tia [17]
2 years ago
4

The Weigelt Corporation has three branch plants with excess production capacity. Fortunately, the corporation has a new product

ready to begin production, and all three plants have this capability, so some of the excess capacity can be used in this way. This product can be made in 3 sizes (large, medium, and small) that yield a net unit profit of $420, $360, and $300, respectively. Plants 1, 2, and 3 have the excess capacity to produce 750, 900, and 450 units per day of this product, regardless of the size or combination of sizes involved.
The amount of available in-process storage space also imposes a limitation on the production rates of the new product. Plants 1, 2, and 3 have 13,000, 12,000, and 5,000 square feet of inprocess storage available for a day’s production of this product. Each unit of the large, medium, and small sizes produced per day requires 20, 15, and 12 square feet, respectively.
Sales forecasts indicate that if available, 900, 1200, and 750 units of the large, medium, and small sizes would be sold per day.
At each plant, some employees will need to be laid off unless most of the plant’s excess production capacity can be used to produce the new product. To avoid layoffs if possible, management has decided that the plants should use the same percentage of their excess capacity to produce the new product.
Management wishes to know how much of each size should be produced by each plant to maximize profit.
Required:
1. Formulate and solve a linear programming model for this mixed problem on a spreadsheet.
2. Express the model in algebraic form.
Business
1 answer:
creativ13 [48]2 years ago
5 0

Answer:

Explanation:

Let xij be the number of units of size j product (j = L, M, S) produced at plant i (i = 1,

2, 3).

The objective is to maximize

Z = 420(x1L + x2L + x3L) + 360(x1M + x2M + x3M) + 300(x1S + x2S + x3S)

subject to the following constraints.

Capacity constraints:

x1L + x1M + x1S ≤ 750

x2L + x2M + x2S ≤ 900

x3L + x3M + x3S ≤ 450

Storage space constraints:

20x1L + 15x1M + 12x1S ≤ 13000

20x2L + 15x2M + 12x2S ≤ 12000

20x3L + 15x3M + 12x3S ≤ 5000

Same capacity percentage constraints:

900(x1L + x1M + x1S) − 750(x2L + x2M + x2S) = 0

450(x2L + x2M + x2S) − 900(x3L + x3M + x3S) = 0

Nonnegativity constraints:

All xij ≥ 0

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