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tankabanditka [31]
2 years ago
9

Plz help!!! Calvin is filling the pool in his backyard with water. If the pool is in the shape of a cylinder with a diameter of

12ft and a height of 5 ft, how much water is needed to fill a 3/4 of the pool?
Mathematics
2 answers:
Gekata [30.6K]2 years ago
4 0

Answer: 424.115

Step-by-step explanation:

(Pi)6^2(5) =565.49

3/4 = 424.115

uysha [10]2 years ago
4 0

Answer:

424.1175

Step-by-step explanation:

Volume of the total pool = πr^{2}h

                                        = π x 6^{2} x 5

                                        = 565.49

needed to fill a 3/4 of the pool = \frac{3}{4} x 565.49

                                                   = <u>424.1175</u>

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Two friends went rowing on the river. They first traveled with current for 3 hours. The way back took them 4 hours and 48 minute
kaheart [24]

Answer:

1.5 mph

Step-by-step explanation:

Let speed of boat be x

let speed of current be c

Also, note D = RT

D is distance

R is rate

T is time

Now, for first leg, we can write:

(x+c)3 = D

And for second leg , we can write:

(x-c)4.8 = D  [note 4 hour 48 minutes is 4.8 hours]

We can equate both D's to get:

(x+c)3 = (x-c)4.8

3x + 3c = 4.8x - 4.8c

7.8c = 1.8x

We know x = 6.5 [given], plugging it in and solving for c:

7.8c = 1.8(6.5)

c = 1.5

Speed of Current = 1.5 miles per hour

3 0
2 years ago
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Sarah buys 2 candy bars for $1.45. how much would one candy bar cost
sattari [20]
2 = $1.45
1 = $0.725

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4 0
2 years ago
Performance task: A parade route must start And and at the intersections shown on the map. The city requires that the total dist
GaryK [48]

Answer:

Part A: The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B: For the total distance is as close to 3 miles as possible, the start point of the parade should be at the point on Broadway with coordinates (9.941, 4.970)

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue; (4, 2)

For Broadway; (7.97, 2.49)

Step-by-step explanation:

Part A: The length of the given route can be found using the equation for the distance, l, between coordinate points as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where for the Broadway potion of the parade route, we have;

(x₁, y₁) = (12, 3)

(x₂, y₂) = (6, 0)

l_1 = \sqrt{\left (0 -3\right )^{2}+\left (6-12 \right )^{2}} = 3 \cdot \sqrt{5}

For the Central Avenue potion of the parade route, we have;

(x₁, y₁) = (6, 0)

(x₂, y₂) = (2, 4)

l_2 = \sqrt{\left (4 -0\right )^{2}+\left (2-6 \right )^{2}} = 4 \cdot \sqrt{2}

Therefore, the total length of the parade route =-3·√5 + 4·√2 = 12.265 unit

The scale of the drawing is 1 unit = 0.25 miles

Therefore;

The actual length of the initial parade =0.25×12.265 unit = 3.09 miles

The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B:

For an actual length of 3 miles, the length on the scale drawing should be given as follows;

1 unit = 0.25 miles

0.25 miles = 1 unit

1 mile =  1 unit/(0.25) = 4 units

3 miles = 3 × 4 units = 12 units

With the same end point and route, we have;

l_1 = \sqrt{\left (0 -y\right )^{2}+\left (6-x \right )^{2}} = 12 - 4 \cdot \sqrt{2}

y² + (6 - x)² = 176 - 96·√2

y² = 176 - 96·√2 - (6 - x)²............(1)

Also, the gradient of l₁ = (3 - 0)/(12 - 6) = 1/2

Which gives;

y/x = 1/2

y = x/2 ..............................(2)

Equating equation (1) to (2) gives;

176 - 96·√2 - (6 - x)² = (x/2)²

176 - 96·√2 - (6 - x)² - (x/2)²= 0

176 - 96·√2 - (1.25·x²- 12·x+36) = 0

Solving using a graphing calculator, gives;

(x - 9.941)(x + 0.341) = 0

Therefore;

x ≈ 9.941 or x = -0.341

Since l₁ is required to be 12 - 4·√2, we have and positive, we have;

x ≈ 9.941 and y = x/2 ≈ 9.941/2 = 4.97

Therefore, the start point of the parade should be the point (9.941, 4.970) on Broadway so that the total distance is as close to 3 miles as possible

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue;

Camera location = ((6 + 2)/2, (4 + 0)/2) = (4, 2)

For Broadway;

Camera location = ((6 + 9.941)/2, (0 + 4.970)/2) = (7.97, 2.49).

5 0
2 years ago
A flower garden has 12 sunflowers for every 45 irises. What is the unit rate for the number of irises per sunflower? Explain how
m_a_m_a [10]

It is given in the question that,

A flower garden has 12 sunflowers for every 45 irises.

And we have to find the unit rate  for the number of irises per sunflower.

And for that we have to divide number of Irises by number of Sunflower. That is

= \frac{45 Irises }{12 Sunflower} = 3.75 Irises \ per \ sunflower .

And that's the required unit rate .

7 0
2 years ago
A Table showing Freezing Temperatures in degrees with 2 columns and 6 rows. The First row, F, has the entries, negative 13, nega
Yuki888 [10]

Answer:

5F + -9  C= 160       39°F = 3.9

Step-by-step explanation:

A Table showing Freezing Temperatures in degrees with 2 columns and 6 rows. The First row, F, has the entries, negative 13, negative 4, 5, 14, 23. The second column, C, has the entries, negative 25, negative 20, negative 15, negative 10, negative 5.

The table shows temperatures below freezing measured in different units. Complete the equation in standard form to represent the relationship between F, a temperature measured in degrees Fahrenheit, and C, a temperature measured in degrees Celsius.

5F + -9 C = 160

39°F = 3.9°C rounded to the nearest tenth of a degree

9 0
2 years ago
Read 2 more answers
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