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Murljashka [212]
2 years ago
15

Within a word processing program, predesigned files that have layout and some page elements already completed are called text bo

xes. templates. frames. typography.
Computers and Technology
1 answer:
Angelina_Jolie [31]2 years ago
7 0

Answer:

I think D, Your welcome :)

Explanation:

 

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Compare the memory organization schemes of contiguous memory allocation and paging with respect to the following issues: a. Exte
Free_Kalibri [48]

Answer:

The comparison is based on memory organization schemes of contiguous memory allocation and paging with respect to External fragmentation, Internal fragmentation and Ability to share code across processes.

Explanation:

Memory organization schemes of contiguous memory allocation:

Contiguous memory allocation schemes suffers from external fragmentation. The reason is that address space is distributed contiguously and the holes and gaps keep growing when the old processes die and new processes are introduced. The variable size partition suffers from external fragmentation however the fixed size partitions do not suffer from external fragmentation. Contiguous memory allocation with variable size partitions does not encounter an internal fragmentation but with fixed size partitions suffers from internal fragmentation. Contiguous memory allocation does not support sharing code across processes. This is because the virtual memory segment of a process is not fragmented into non-contiguous fine grained blocks.

Paging:

Paging does not encounter external fragmentation as pages are of the fixed or equal size. So this reduces external fragmentation. However paging suffers from internal fragmentation. This is because a process can request more space or it can request for a less space. When page is allocated to the such a process that page is no longer utilized.This results in internal fragmentation because of the wastage of space even when the page has internal space but cannot be fully utilized. Paging allows to share code across processes.

5 0
2 years ago
Which of the following is an advantage of inserting a page number field in your document rather than inserting each page number
Artyom0805 [142]

The advantage of inserting the page number field is that the page number field could show the current page number.

The following information should be relevant with respect to the page number:

  • The page number field & the actual page number should be formatted.
  • The page number field & the actual page number both could be inserted into the header or footer.
  • The page number field & the actual page number could be easily inserted into the document.

Therefore we can conclude that the advantage of inserting the page number field is that the page number field could show the current page number.

Learn more about the page number here: brainly.com/question/3063419

8 0
2 years ago
In a single file, you wrote a bike class and used this line of code in the program.
Elza [17]

Answer:

Explanation:

Based on the available options the one that would be correct would be that the code to define your class (beginning with "class bike") must come before the line "bikeA = bike('Acme' 111)." This is because the line of code declaring the object and initializing it needs to be able to grab the information of the class that it is creating an object of. To do this, the class would need to have already been compiled by the program. It is good practice to have each class definitions as its own separate files but this is not a necessity.

5 0
2 years ago
Open "Wireshark", then use the "File" menu and the "Open" command to open the file "Exercise One.pcap". You should see 26 packet
murzikaleks [220]
Idk idk idk idk idk idk
8 0
2 years ago
Write code that uses the input string stream inss to read input data from string userinput, and updates variables usermonth, use
mr Goodwill [35]

Answer:

It will be a java code.

Explanation:

import java.util.Scanner;

public class StringInputStream {

    public static void main (String [] args) {

        Scanner inSS = null;

        String userInput = "Jan 12 1992";

        inSS = new Scanner(userInput);`

        String userMonth = "";

        int userDate = 0;

        int userYear = 0;

        /* Your solution goes here  */

        System.out.println("Month: " + userMonth);

        System.out.println("Date: " + userDate);

        System.out.println("Year: " + userYear);

        return;

   }

}

3 0
2 years ago
Read 2 more answers
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