We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
Answer:
A. f(s) = 2s + 34
B. Mole
C. f(s) = 2s + 54
Step-by-step explanation:
A. Its a prediction the 34 can be any number reasonably close to 25
B. Amount of substance - mole (mole)
c. f(s) = 2s + 54
Answer:
2
Step-by-step explanation:
Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2
Substituting π/2 into the function
lim x-->π/2 sin(x)-1/cos 2(x)
= sin(π/2) - 1/cos(2)(π/2)
= 1 - 1/cosπ
= 1- 1/-1
= 1 -(-1)
= 1+1
= 2
Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2
Answer:
See below
Step-by-step explanation:
<h3>Continuation of the question</h3>
<u>Data in the table:</u>
<u>PH 4 5 6 7 8 9 10 11 </u>
<u>Bacteria 116 120 131 136 141 151 148 163</u>
- <em>Create a scatter plot to represent the data: Based on the data and your scatter plot, what do you think a good linear function would be to represent the data?</em>
<h3>Solution</h3>
<em>See attached for scatter plot</em>
We can see the chart is close to linear function. Let's build one based on data in the table
<u>The line will be in the form of:</u>
<u>If we use two points and get the equation</u>
<u>Finding the slope:</u>
- m = (141-116)/(8-4) = 25/4 = 6.25
<u>Then, finding y-intercept:</u>
- 116 = 6.25*4 + b
- b = 116 - 25 = 91
<u>So the line is:</u>
<em>Note: This is approximate best fit graph and it is attached as well. Exact formula for the line is built by using different method and is very close to the one above</em>
Answer:
35°
Step-by-step explanation:
We assume that points S, T, U, V all lie on the circle.
Inscribed angle TUV intercepts long arc VST and short arc VUT. The long arc has measure 220°, so the measure of the short arc is 360° -220° = 140°.
Since chords UV and UT are the same length, point U bisects arc VUT. That means the measure of arc VU is 140°/2 = 70°.
Inscribed angle VSU intercepts arc VU, so has half the measure of the arc:
∠VSU = 70°/2
∠VSU = 35°
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