In order to solve this, you have to set up a systems of linear equations.
Let's say that children = c and adults = a
30a + 12c = 19,080
a + c = 960
I'm going to show you how to solve this system of linear equations by substitution, the easiest way to solve in my opinion.
a + c = 960
- c - c
---------------------- ⇒ Step 1: Solve for either a or c in either equation.
a = 960 - c
20(960 - c)+ 12c = 19,080
19,200 - 20c + 12c = 19,080
19,200 - 8c = 19,080
- 19,200 - 19,200
---------------------------------- ⇒ Step 2: Substitute in the value you got for a or c
8c = -120 into the opposite equation.
------ ---------
8 8
c = -15
30a + 12(-15) = 19,080
30a - 180 = 19,080
+ 180 + 180
-------------------------------
30a = 19,260
------- -----------
30 30
a = 642
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I just realized that there can't be a negative amount of children, so I'm sorry if these results are all wrong.
For the same payment and term, the lower the interest rate, the more the loan can be. The opposite is also true. The appropriate selection is ...
B. If the interest rate were 6.8%, the amount of the loan Bill is considering taking out would be less than $33,025.69.
_____
At 6.8%, Bill can afford a loan of $32,585.93.
Week 1 = 5 guppies.
week 2 = 5x 2 = 10 guppies
week 3 = 10 x 2 = 20 guppies
week 4= 20 x 2 = 40 guppies
week 5 = 40 x 2 = 80 guppies
week 6= 80 x 2 = 160 guppies
Yuki had 160 guppies in 6 weeks.
The correct answer to this is:
Nonrandom and biased
<span>The method of Li’s sampling has a
tendency that some elements or portion in the population has no chance of
selection. Further, it was not stated which portion of the population she
obtained the sample thus we cannot accurately determine the probability of
selection. This kind of sampling results in a bias. A biased sampling is a type
of nonrandom sampling. </span>
The formula for interval estimate would be: μ = M ± Z(<span>sM</span>)
Where: μ is estimate
M is the mean
Z is the z value
(<span>sM</span>) is the standard
error
μ = M ± Z(<span>sM</span>)
n = 200 rather than 50 (√200 = 2√50)
<span>⇒ ME = (1/2) * 1.32 = .66</span>
<span>Using the formula above, plugging this in will give us: μ
= 19.76 ± .66</span>
<span> = 19.76 ± .66 is
the confidence interval or interval estimate</span>
