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nevsk [136]
2 years ago
4

Triangles A B C and X Y Z are shown. Angles A B C and X Y Z are right angles. Angles B A C and Y X Z are congruent. The length o

f A B is 5, the length of A C is 13, and the length of B C is 12. Given △ABC ~ △XYZ, what is the value of cos(Z)? Five-thirteenths Five-twelfths Twelve-thirteenths Twelve-fifths
Mathematics
2 answers:
solong [7]2 years ago
8 0

Answer:

The answer is C on Edge 2020

Step-by-step explanation:

DiKsa [7]2 years ago
6 0

Answer:

12/13

Step-by-step explanation:

just did it on edg

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Write an expression that evaluates to true if the int associated with number_of_prizes is divisible (with no remainder) by the i
hodyreva [135]

We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.

Let us assume number of Prizes are = p and

Number of participants = n.

If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.

Let us assume that quotent is taken by q.

So, we can setup an expression now.

Let us rephrase the statement .

" Number of Prizes ÷ Number of participants  = quotient".

p ÷ n = q.

In fraction form we can write

p/n =q   ; n ≠ 0.


4 0
2 years ago
Given a normal distribution with u = 75 and o = 40, if you select a sample of n = 16, a) what is the probability that the sample
Volgvan

Answer:

a) 0.0228

b) 94.6

Step-by-step explanation:

The formula for calculating a z-score when you are given a random.number of samples is z = (x-μ)/σ/√n

where x is the raw score

μ is the population mean

σ is the population standard deviation

n = random number of samples

Given a normal distribution with u = 75 and o = 40, if you select a sample of n = 16,

a) what is the probability that the sample mean is above 95? (4 d.p.) b)

= x = 95

Hence:

z = 95 - 75/40/√16

= 20/40/4

= 20/10

= 2

Probability value from Z-Table:

P(x<95) = 0.97725

P(x>95) = 1 - P(x<95) = 0.02275

The probability that the sample mean is above 95 to 4 decimal places = 0.0228

b) What is the value, of which there is 97.5% chance that a sample mean is less than that value?

97.5% chance = z score for the confidence interval = 1.96

Hence:

z = (x-μ)/σ/√n

1.96 = x - 75/40/√16

1.96 = x - 75/ 40/4

1.96 = x - 75/10

Cross Multiply

1.96 × 10 = x - 75

19.6 = x - 75

x = 19.6 + 75

x = 94.6

The value, of which there is 97.5% chance that a sample mean is less than that value is 94.6

5 0
2 years ago
give me 3 pictures showing the application of the sum and the product of the roots of quadratic equations in real life . describ
Vlada [557]

We can apply Quadratic equations in real-world like; sports, bridges, projectile motion, shapes of bananas etc.

Following are three pictures of real world application of quadratics.

Example 1:- Here we can see a Cyclist follows a quadratic path to jump over the obstacles.

Example 2:- Here we see a man throwing a basketball towards the net following a slightly upward direction that goes through a quadratic path.

Example 3:- Here a football player kicks the ball in the sky and it goes through a quadratic path to cover some distance.

4 0
2 years ago
Read 2 more answers
A baker’s dozen (13) of cookies is on sale for $2.08.
poizon [28]
So taking this as if there are 13 dozens of cookies. First we do 13 times 12 which would be 156 cookies in total. Then 156 cookies times 2.08 is 324.48
4 0
2 years ago
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State whether the given measurements determine zero, one, or two triangles. A = 61Á, a = 23, b = 24
Assoli18 [71]

The given measurements determine one triangles, A = 61Á, a = 23, b = 24 because the triangle can be defined using those 3 data, first is using the sine law to solve another angle. Then using cosine law to solve the third side. Lastly solving the 3rd angle by difference.

6 0
2 years ago
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