Write the inequalities that are given by the :
<span>x: the number of batches of muffins
y: the number of batches of cakes
</span>Each batch of muffin requires 7 liters of milk and each batch of cakes
require 4 liters of milk.
=> liters of milk use = 7x + 4y
<span>Tania
has 56 liters of milk.=> 7x + 4y ≤ 56
Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.
The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.
The line 7x + 4y = 56 has these x and y intercepts:
y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)
x-intercept => y = 0 => 7x = 56 => x = 56/7= 8 => point (8,0)
So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.
Also, you know that x and y are restricted to be positive or zero =>
x ≥ 0
y ≥ 0.
So, the solution region is restricted to the first quadrant.
That implies that the answer is:
</span><span>
Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
</span>
Answer:
All the expressions other than option E, is equivalent to the expression 18m - 12.
Step-by-step explanation:
A. 6m - 4 + 6m -4 + 6m - 4
or 6m+6m+6m -4 -4 -4
or 18m -12
B. 12m + 6 - 6m -6
or 12m - 6m + 6 - 6
or 6m
C.6(3m - 2)
or 18m - 12
D.3(6m - 4)
or 18m - 12
E. 24n - 4² + 8 -6m
This option can not satisfy the given expression as it contains another variable as n.
Well you are look at a 3d image here
so if area is length times width then we need to find the area of every side of the cabinet and add it up
11/3 on the calculator is 3.66666667 sooooo....
top: 3 x 11/3 = 11
side 1: 3 x 6 = 18
side 2: 3 x 6 = 18
front: 6 x 11/3 = 22
back: 6 x 11/3 = 22
so we have all of our measurements:)
now we just add them up together.
11+18+18+22+22= 91!!
so Frans would have to paint 91 square inches of that cabinet:) hope i helped
Answer:
The correct answer is
(0.0128, 0.0532)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence interval
, we have the following confidence interval of proportions.

In which
Z is the zscore that has a pvalue of 
For this problem, we have that:
In a random sample of 300 circuits, 10 are defective. This means that
and 
Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.
So
= 0.05, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The correct answer is
(0.0128, 0.0532)
Answer:
18, 21, 36
Step-by-step explanation:
Let L represent the least number. Then the greatest is 2L and the middle number is (L+3). Their sum is ...
L +(2L) +(L+3) = 75
4L = 72 . . . . . . . . . subtract 2, collect terms
L = 18 . . . . . . . . . . . divide by 4
L+3 = 21
2L = 36
The numbers are 18, 21, and 36.