Answer:
N(24, 3.46)
Step-by-step explanation:
We are given the following in the question:
Percentage of family homes having front poach = 50%

Sample size, n = 48
Normal approximation to the given distribution:


Thus, the distribution of single family homes is best approximated by the normal distribution N(24, 3.46) where mean is 24 and standard deviation is 3.46
Answer:
The correct answer is option B. 17
Step-by-step explanation:
It is given that, ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°
To find the value of m
From the figure we can see that, triangle WYZ is an isosceles triangle.
ZW = ZY
Then <YXZ = <WXZ = 90°
It is given ∠YXZ = (6m – 12)°
(6m – 12)° = 90°
6m = 90 + 12 = 102
m = 102/6 = 17
Therefore the value of m = 17
The correct answer is option B. 17
Her school is 2/3 miles away
2/3=4/6miles
So we need to find out how long it will take for her to run home from school...
School=4/6 miles
In 1 minutes she can run 1/6 miles
1min=1/6miles
In 2 minutes she can run 1/6+1/6 miles (1/6+1/6=2/6)
2min=2/6miles
3min=3/6miles
4min=4/6miles
It will take Erica 4 minutes to run 4/6 miles, so it'll take her 4 minutes to get home.
Answer:
The answer is (D) ⇒ a = 11.71 , b = 15.56
Step-by-step explanation:
* In ΔABC
∵ m∠A = 45°
∵ m∠B = 110°
∴ m∠C = 180 - 45 - 110 = 25°
By using the sin Rule
∵ a/sin(A) = b/sin(B) = c/sin(C)
∵ c = 7
∴ a/sin(45) = b/sin(110) = 7/sin(25)
∴ a = (7 × sin(45)) ÷ sin(25) = 11.71
∴ b = (7 × sin(110)) ÷ sin(25) = 15.56
∴ The answer is (D)
Answer:
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Step-by-step explanation:
We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.26.
The standard error of the proportion is:
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:

Then, the lower and upper bounds of the confidence interval are:

The 95% confidence interval for the population proportion is (0.192, 0.328).
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.