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zhuklara [117]
2 years ago
13

Brian skied for 0.75 hours at an average speed of 9.25 miles per hour. His sister Tori calculated the distance Brian skied. Tori

’s work is shown below. 9.25 times 0.75 = 4625. 4625 + 6475 = 11.090 miles. What errors did Tori make when solving the problem? all that apply.
A)She multiplied 5 and 925 incorrectly
B)She did not correctly align the place values of the partial products.
C)She did not place the decimal point correctly.
D)She added the partial products incorrectly.
Mathematics
2 answers:
mote1985 [20]2 years ago
7 0

B, C, and D. I took da test.

Darya [45]2 years ago
3 0

b, c, and d

are all of the answers

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) If the pattern shown continues, how many black keys appear on a portable keyboard with 49 white keys? Suggestion: use equivale
andriy [413]

Answer:

35

Step-by-step explanation:

Here we see 5 black keys for every 7 white keys.

So the ratio is 5:7

If we need 49 white keys, find the amount we scale the original ratio by:

    49/7 = 7

So we are scaling by a factor of 7.

The number of black keys would be 5 * the scale of 7. = 35

So there should be 35 black keys.

5 0
1 year ago
Read 2 more answers
There are 200 students in the 7th grade class at Brookside Middle School. Of these students, 12% play volleyball and 15% play ba
Phoenix [80]
P(volleyball and baseball) = 4/200 x 100 = 2%
P(either volleyball or baseball) = P(volleyball ∪ baseball) = P(volleyball) + P(baseball) - P(volleyball and baseball) = 12% + 15% - 2% = 25%.

25% play either volleyball or baseball.
4 0
2 years ago
Read 2 more answers
You are in a bike race. When you get to the first checkpoint, you are 25 of the distance to the second checkpoint. When you get
Rom4ik [11]

Question:

You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?

Answer: 4 miles

Step-by-step explanation:

Let distance between start to first checkpoint = x

First checkpoint to second checkpoint = 2/5 of x

Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)

Distance of start to checkpoint 2 = (1/4 of start to finish)

If start to checkpoint 2 = 1/4 of start to finish

Then,

Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)

Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish

Entire race = 40 miles = distance from start to finish

1/ 10 of 40

= ( 1/10) × 40

= 4 miles

6 0
2 years ago
A
gavmur [86]

Answer:

m∠QPM=43°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠NPQ=m∠MPN+m∠MPQ

we have

m∠NPQ=(9x-25)°

m∠MPN=(4x+12)°

m∠MPQ=(3x-5)°

substitute the given values and solve for x

(9x-25)°=(4x+12)°+(3x-5)°

(9x-25)°=(7x+7)°

9x-7x=25+7

2x=32

x=16

Find the measure of angle QPM

Remember that

m∠QPM=m∠MPQ

m∠MPQ=(3x-5)°

substitute the value of x

m∠MPQ=(3(16)-5)=43°

therefore

m∠QPM=43°

7 0
2 years ago
You are considering the purchase of a closed circuit TV monitoring system for your store. The quarterly physical inventory has s
Tcecarenko [31]
If quarterly shrinkage (every 3 months) is 2.5%, then multiplying by $875,495 gives a value of 21887.38, or an average monthly shrinkage of 21887.38 / 3 = $7,295.79.For an employee to monitor the CCTV, it would cost ($7.5/h)(11 h/d)(30 d/m) = $2,475/month. Therefore, it is much cheaper (around 2/3 cheaper) to have an employee monitor CCTV rather than to allow the high shrinkage rate.

7 0
2 years ago
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