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2 years ago

What is csc of angle b. reduce fractional answers to lowest terms

Mathematics

1 answer:

kupik [55]2 years ago

3 0

Answer:

17 / 8

Step-by-step explanation:

So the cosecant is equal to the hypotenuse ÷ opposite side

Hypotenuse = 17

Opposite side = 8

17 / 8

You might be interested in

What is the length of segment XY?

Brilliant_brown [7]

Answer:

StartRoot 53 EndRoot units

XY = √53

Step-by-step explanation:

Choose which is point 1 and point 2 so you don't confuse the coordinates.

Point 1 (–4, 0) x₁ = –4 y₁ = 0

Point 2 (3, 2) x₂ = 3 y₂ = 2

Use the formula for the distance between two points.

$L = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$

$XY = \sqrt{(3-(-4))^{2} + (2-0)^{2}}$

$XY = \sqrt{49 + 4}$

$XY = \sqrt{53}$

Therefore the line of segment XY is √53.

6 0

2 years ago

Read 2 more answers

What is the value of (5x²)³ + 16y divided by 4y for x=2 and y=3

Inessa05 [86]

Answer:

30 2/3

Step-by-step explanation:

First multiply the two exponents

Second solve 2^6

Third multiply 64 times 5 = 320

Then multiply 16 times 3

Then add sums together 368

Lastly multiply 4 times 3 then divide 368 by 12

I hope this helps :)

6 0

2 years ago

Let e1= 1 0 and e2= 0 1 , y1= 4 5 , and y2= −2 7 , and let T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps

Furkat [3]

Answer:

The image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is $\left[\begin{array}{c}24&-8\end{array}\right]$

Step-by-step explanation:

We know that $T:$ $IR^{2}$ → $IR^{2}$ is a linear transformation that maps $e_{1}$ into $y_{1}$ ⇒

$T(e_{1})=y_{1}$

And also maps $e_{2}$ into $y_{2}$ ⇒

$T(e_{2})=y_{2}$

We need to find the image of the vector $\left[\begin{array}{c}4&-4\end{array}\right]$

We know that exists a matrix A from $IR^{2x2}$ (because of how T was defined) such that :

$T(x)=Ax$ for all x ∈ $IR^{2}$

We can find the matrix A by applying T to a base of the domain ( $IR^{2}$ ).

Notice that we have that data :

$B_{IR^{2}}=$ { $e_{1},e_{2}$ }

Being $B_{IR^{2}}$ the cannonic base of $IR^{2}$

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

$T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]$ (Data of the problem)

$T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]$ (Data of the problem)

Writing the matrix A :

$A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]$

Now with the matrix A we can find the image of $\left[\begin{array}{c}4&-4\\\end{array}\right]$ such as :

$T(x)=Ax$ ⇒

$T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]$

We found out that the image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is the vector $\left[\begin{array}{c}24&-8\end{array}\right]$

3 0

2 years ago

A tank holds 49 litres of oil. if 7 litres leaked what percentage of oul has leaked

REY [17]

Answer:

14.3%

Step-by-step explanation:

7 liters of the 49 litre oil has been poured out. Since it is out of 49, divide 7 by 49 and multiply by 100 to find its percentage. bangg.

6 0

1 year ago

Shania is making a scale diagram of the badminton court at the community center. She uses a scale of 1 centimeter to 0.5 meter t

docker41 [41]

1m = 100cm

1cm → 0.5m

1cm → 0.5 · 100cm = 50cm

The scale: $\dfrac{50}{1}=50$

length = 26.8cm · 50 = 1,340cm = 13.40m

width = 12.2cm · 50 = 610cm = 6.10m

The area of the court:

A = 13.40 · 6.10 = 81.74 m²

8 0

2 years ago