So let’s substitute that into the
third equation and solve for B. B = H + T B = 9 + (9 + 1/2B) B = 18 + 1/2B Then
subtract 1/2B from both sides: 1/2B = 18 Multiply both sides by two: B = 36 Now
we know the value of B and the value of H. Substitute this back into the second
equation and solve for T. T = H + 1/2B T = 9 + (1/2)36 T = 9 + 18 = 27 Step 4:
Plug all values of H, T, and B into the final equation. Total length of fish =
H + T + B Total length of fish = 9 +27 + 36 = 72.
Answer:
Approximately it will consume 55% of the total time in the interphase i.e. 800 minutes.
Explanation:
The time required in different phases are as follows:
It takes 800 minutes for interphase
It takes 400 minutes for prophase
It takes 120 minutes for metaphase
It takes 80 minutes for anaphase
It takes 40 minutes for telophase
Total -- 24 hours
From this it can be concluded that around 55% of the time spent in the interphase, whereas only 28% in the prophase, 8% time for metaphase, 6% Anaphase and 3% Telophase. This is all happens in the onion cell but in case of the human cell, prophase it takes about 15 min, in prometaphase it takes 15 mins, metaphase takes in about 20 min, Anaphase takes minimum of 3 min and telophase is about and cytokineses are about less then 10 mins.
There are 6 molecules of O2.
"O2" is the formula for one molecule oxygen, which has 2 atoms.
The subscript (small) "2" tells you how many atoms are in the molecule.
The coefficient is the big number tells you the number of molecules.
In 6O2, there are 12 atoms in total (6 molecules of 2 atoms each).
There are 384 fluid ounces in 3 gallons. The teacher does not have enough for each student to have 12 fluid ounces.
384÷12=32
4 students would go thirsty.
