Answer:
Genetic diversity: Some individuals in a population of wild rabbits are resistant to a new disease.
Ecosystem diversity: If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks.
Species diversity: Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation.
Biodiversity of an ecosystem is usually explored by three diversities which are responsible for ecosystem stability they are : genetic diversity, ecosystem diversity and species diversity.
Genetic diversity is the variety of genes within a population of species. Each species consists of individuals bearing different genetic composition. Some individuals in a population of wild rabbits are resistant to a new disease because they exhibit genetic diversity within the population as a consequence some individuals exhibit genes which protect them against new disease.
Species diversity is the variety of species within an ecosystem. Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation is an example of species diversity. The wild rabbits from a forest and a neighboring meadow are two species living in an ecosystem stating the diversity of species in an ecosystem.
Ecosystem diversity is the variety of ecosystems in a given region.If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks is an example of ecosystem diversity because in an ecosystem there is interaction of organisms as predator prey relationship. This example is also relating with predator prey relationships in an ecosystem.
Universities and Colleges: Professor
Sea Parks: Aquarist
Federal and State Departments: Enviornmental Consultant
Marine Related Industires: Marine Researcher
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there isn't enough details to answer the question Sopa Maru
Answer:
Error: The Methionine at the end of the chain
Explanation:
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The start codon is AUG, this codon encodes Methionine. Therefore all proteins will start the amino acid sequence with Methionine.
In this case, the student placed the Methionine at the end of the chain, so that is the mistake. Methionine goes to the beginning of the chain.