Answer:
The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
Step-by-step explanation:
We have a rectangular base, that its twice as long as it is wide.
It must hold 12 yd^3 of debris.
We have to minimize the surface area, subjet to the restriction of volume (12 yd^3).
The surface is equal to:

The volume restriction is:

If we replace h in the surface equation, we have:

To optimize, we derive and equal to zero:
![dS/dw=36(-1)w^{-2} + 8w=0\\\\36w^{-2}=8w\\\\w^3=36/8=4.5\\\\w=\sqrt[3]{4.5} =1.65](https://tex.z-dn.net/?f=dS%2Fdw%3D36%28-1%29w%5E%7B-2%7D%20%2B%208w%3D0%5C%5C%5C%5C36w%5E%7B-2%7D%3D8w%5C%5C%5C%5Cw%5E3%3D36%2F8%3D4.5%5C%5C%5C%5Cw%3D%5Csqrt%5B3%5D%7B4.5%7D%20%3D1.65)
Then, the height h is:

The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
Answer:
(a) 12π in
(b) 53.5 in
(c) 96 grams
Step-by-step explanation:
In the figure attached, the ornament is shown
(a) four three-quarter circles is equivalent to 4*3/4 = 3 circles. The perimeter of a circle is the total length of the circular portions.
Perimeter of each circle: 2*π*r
The radius is 2 in long, then for 3 circles:
Perimeter = 3*2*π*2 = 12π in
(b) Perimeter of square: 4*side length
The side length of the square is 4 in, then:
Total length of wire needed = 4*4 + 12π = 53.5 in
(c) The wire weighs 1.8 grams per inch, then:
total weight of the ornament = 1.8 grams/in * 53.5 in = 96 grams
The residual value or some may term it the salvage value is the value of an item after a certain period of time. Let x be the original msrp (manufacturer suggested retail price), we can calculate for the salvage value as follows:
12,780 = 0.72x
The value of x from the equation generated above is 17,750. Therefore, the original msrp is equal to $17,750.
Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595 (1)
s + 15 = r (2)
Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595 Combine like terms
2s + 15 = 1595 Subtract 15 from both sides
2s = 1595 - 15
2s = 1580 Divide by 2
s = 1580/2
s = 795 sophmores.
s + r = 1595
795 + r = 1595 Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen
Answer C <<<<<<