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zhannawk [14.2K]
2 years ago
9

Hugo plans to buy packs of baseball cards until he gets the card of his favorite player but he only has enough money to buy at m

ost four packs. Suppose that each pack has a probability of 0.20 of containing the card Hugo is hoping for. Find the probability that it takes three or more packs to get the card of his favorite player.
Mathematics
1 answer:
nataly862011 [7]2 years ago
3 0

Answer:

Step-by-step explanation:

This is an example of a geometric probability distribution because trials are repeated until the first success is gotten. Since each pack has a probability of 0.20 of containing the card Hugo is hoping for, it means that the probability of success, p = 0.2.

Let x represent the number of packs it takes to get the card of his favorite player. The the probability that it takes three or more packs to get the card of his favorite player is expressed as

P(x ≥ 3)

By using the geometric distribution calculator,

P(x ≥ 3) = 0.64

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Suppose X is the breaking strength (newtons) of a material, and X is normally distributed with
Veronika [31]

Answer:

a) 0.997 is the  probability that the breaking strength is at least 772 newtons.

b) 0.974  is the probability that this material has a breaking strength of at least 772 but not more  than 820    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 800 newtons

Standard Deviation, σ = 10 newtons

We are given that the distribution of  breaking strength is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( breaking strength of at least 772 newtons)

P(x \geq 772)

P( x \geq 772) = P( z \geq \displaystyle\frac{772 - 800}{10}) = P(z \geq -2.8)

= 1 - P(z

Calculation the value from standard normal z table, we have,  

P(x \geq 772) = 1 - 0.003 = 0.997 = 99.7\%

0.997 is the  probability that the breaking strength is at least 772 newtons.

b) P( breaking strength of at least 772 but not more  than 820)

P(772 \leq x \leq 820) = P(\displaystyle\frac{772 - 800}{10} \leq z \leq \displaystyle\frac{820-800}{10}) = P(-2.8 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2.8)\\= 0.977 - 0.003 = 0.974 = 97.4\%

P(772 \leq x \leq 820) = 97.4\\%

0.974  is the probability that this material has a breaking strength of at least 772 but not more  than 820.

7 0
2 years ago
The exhaust system of an automobile is first given an emission check and then given a vibration check. The result of an emission
Andre45 [30]

Answer:

Step-by-step explanation:

The sample space is known to be the set of all possible outcomes of an experiment we cannot predict its outcome while the event space showcases the subset of the sample space, this may be a collection of outcomes of a random experiment.

From the given information:

The sample space = {SH, SL, SN, MH, ML, MN,UH, UL, UN}

The event that the emissions check is satisfactory = {SH, SL, SN}

8 0
1 year ago
The average length of time that three lawn-service mowers operate on a given day is 930 minutes. None of the mowers operates for
Zielflug [23.3K]

Answer:

The answer is <u>A. 990.</u>

Step-by-step explanation:

Now, to find the greatest possible length of time any of the mowers operates.

The 3 lawn-service mowers operate at the average length of time = 930 minutes.

So, the total length of time the 3 lawn mowers take = 930\times 30=2790\ minutes.

The least length a mowers operates = 900 minutes.

Now, to find the greatest possible length of time any of the mowers operates:

Let x be the greatest possible length of time any of the mowers operates.

<em>As, any one of the mowers operates greatest length.</em>

<em>So, rest of the two mowers be least at length.</em>

According to question:

x+900+900=2790

x+1800=2790

<em>Subtracting both sides by 1800 we get:</em>

x=2790-1800

x=990.

<u><em>Thus, the greatest possible length of time any of the mowers operates is 990 minutes.</em></u>

Therefore, the answer is A. 990.

3 0
2 years ago
What is the probability of rolling an odd number and spinning "B," given the sample space below? 1 2 3 4 5 6 A A1 A2 A3 A4 A5 A6
Zielflug [23.3K]
There are 3 odd numbers out of 6 numbers and  7 B's out of  28  so

required probability =  3/6 * 7/28 = 1/2 * 1/4 = 1/8 Answer
6 0
3 years ago
Suri made 6 gallons of lemonade to sell at her lemonade stand. in one day she sold 2/3 of the lemonade. how much lemonade did sh
Zina [86]
I hope this helps you

7 0
2 years ago
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