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kobusy [5.1K]
2 years ago
11

Toy train A crosses a pole after every 24seconds. Toy train B crosses the pole after every 30 seconds and toy train C crosses th

e pole after every 36 seconds. After how many minutes, do they all cross the pole together?
Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
6 0

Answer: 6 minutes

Step-by-step explanation:

From the question, Toy train A crosses a pole after every 24seconds while Toy train B crosses the pole after every 30 seconds and then toy train C crosses the pole after every 36 seconds. We are going to solve this by finding their lowest common multiple (LCM).

24 = 24, 48, 72, 96, 120, 144, 168, 192, 216, 240, 264, 288, 312, 336, 360.

30 = 30, 60, 90, 120, 150, 180, 210, 240, 270, 300, 360, 390

36 = 36, 72, 108, 144, 180, 216, 252, 288, 324, 360.

We can see that the lowest common multiple of 24, 30 and 36 is 360.

Since 60 seconds make 1 minute, this will be converted to minutes.

= 360/60

= 6 minutes.

They all cross the pole together after 6 minutes.

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Fez rolls 2 fair dice and adds the results from each. Work out the probability of getting a total less than 6.
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Answer:

The probability of getting  sum of two dice is less than six

P(E) =0.25

Step-by-step explanation:

<u><em>Step(i):-</em></u>

The total number of cases n(S) = 6² = 36

Let 'E' be the event of getting  sum of two dice is less than six

{(1,2) , (1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}

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P(E) = \frac{9}{36} = \frac{1}{4}

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Answer:

  3

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Your problem statement tells you ....

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--------------------------

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Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
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hope this helps
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