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liq [111]
1 year ago
12

Un kg de banane costa cat doua kilograme de portocale . Un restaurant a cumparat 30 de kg de portocale si 45 de kg de banane , p

entru care a platit 360 de lei . Determinati pretul unui kg de portocale.
am nevoie urgent de raspuns .
Mathematics
1 answer:
Nimfa-mama [501]1 year ago
5 0

Answer:

<h2>One kilogram of oranges cost $3.</h2>

Step-by-step explanation:

The problem states

  • 1 kilogram of bananas costs as much as 2 kilograms of oranges. (1 \ kg \ bananas = 2 \ kg  \ oranges)
  • 30 kilograms of oranges plues 45 kilograms of bananas cost $360.

Let's call x one kilogram bananas and y one kilogram oranges. The cost is related by

x=2y

Also, we know by given

45x+30y=360

Replacing the first equation into the second one, we have

45(2y)+30y=360\\90y+30y=360\\120y=360\\y=\frac{360}{120}\\ y=3

Then, we find the other value

x=2(3)=6

Therefore, one kilogram of oranges cost $3.

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Two horses are ready to return to their barn after a long workout session at the track. the horses are at coordinates H(1,10) an
ss7ja [257]
The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B  = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters


Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B  = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.

4 0
2 years ago
(GEOMETRY only answer if u know) Is rectangle EFGH the result of a dilation of rectangle ABCD with a center of dilation at the o
ololo11 [35]

Answer:

option: b is correct.

( b.Yes, because both figures are rectangles and all rectangles are similar )

Step-by-step explanation:

Yes, the rectangle EFGH is a result of dilation of rectangle ABCD with a center of dilation at the origin.

Also The scale factor of the dilation is greater than one as the image is bigger than the pre-image i.e. there is a stretch.

The scale factor could be calculated by the ratuio of the sides of the image to the pre-image rectangle.

Rectangle ABCD: Its vertices have coordinates A(-3,3), B(3,3), C(3,0) and D(-3,0).

Now consider rectangle EFGH:  Its vertices have coordinates E(-4,4), F(4,4), G(4,0) and H(-4,0).

Hence the scale factor is:

\dfrac{EF}{AB}=\dfrac{EH}{AD}=\dfrac{FG}{BC}=\dfrac{HG}{DC}=\dfrac{4}{3}

Hence the scale factor is: 4/3.

Also

∠A=∠B=∠C=∠D=∠E=∠F=∠G=∠H=90°

( When a shape is dilated the two shapes are similar.And similar shapes have equal interior angles , corresponding sides are proportional ).

Hence option: b is correct.

( b.Yes, because both figures are rectangles and all rectangles are similar )

3 0
2 years ago
Read 2 more answers
How long is a distance of 8 km if measured on a map with a scale of 1:50,000
quester [9]
Since this is a ratios and proportions problem, you would set up the equation like this:
1/50,000  = x/8                      x is the length of the distance on the map

After that, you cross multiply and you will get 50,000x=8  
You then solve for x to get 0.00016
6 0
2 years ago
2 (x + 1) - 3 cuando x = 6​
katen-ka-za [31]

Answer:

11

Step-by-step explanation:

6+1=7

7x2=14

14-3=11

espero que esto ayude

3 0
2 years ago
Read 2 more answers
Dave found that about 8/9 of the students in his class have a cell phone.What percent of the students in his class do NOT HAVE a
iris [78.8K]
If the number of students in the class is considered to be 1, and 8/9 of the students have a cell phone, the fraction indicating the number of students who do not have a cell phone is:
1- 8/9= 1/9.

1/9 of the students don't have a cell phone~
6 0
2 years ago
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