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liq [111]
2 years ago
12

Un kg de banane costa cat doua kilograme de portocale . Un restaurant a cumparat 30 de kg de portocale si 45 de kg de banane , p

entru care a platit 360 de lei . Determinati pretul unui kg de portocale.
am nevoie urgent de raspuns .
Mathematics
1 answer:
Nimfa-mama [501]2 years ago
5 0

Answer:

<h2>One kilogram of oranges cost $3.</h2>

Step-by-step explanation:

The problem states

  • 1 kilogram of bananas costs as much as 2 kilograms of oranges. (1 \ kg \ bananas = 2 \ kg  \ oranges)
  • 30 kilograms of oranges plues 45 kilograms of bananas cost $360.

Let's call x one kilogram bananas and y one kilogram oranges. The cost is related by

x=2y

Also, we know by given

45x+30y=360

Replacing the first equation into the second one, we have

45(2y)+30y=360\\90y+30y=360\\120y=360\\y=\frac{360}{120}\\ y=3

Then, we find the other value

x=2(3)=6

Therefore, one kilogram of oranges cost $3.

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Tony’s class needs more than $500 for the school dance. So far, they have raised $200. They plan to have a car wash, charging $8
Orlov [11]

Answer: no Tony is not correct It is less than 5 hundred dollars.

Step-by-step explanation: 8×37=296 +200 = 496

4 0
2 years ago
Read 2 more answers
A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​
Leno4ka [110]

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

7 0
2 years ago
Jan accidentally ran 7 minutes longer than she was supposed to. Write an expression for the total amount of time Jan ran if she
vovangra [49]

Answer:

m+7

Step-by-step explanation:

If she ran 7 minutes longer and m represents the amount of time she ran, then it would just be addition.

Let's say m=60 minutes. She would've ran for 67 minutes, which is also m+7.

6 0
2 years ago
Annie is creating a stencil for her artwork using a coordinate plane. The beginning of the left edge of the stencil falls at (2,
taurus [48]

Answer:

(A)(12, 9)

Step-by-step explanation:

Given:

The beginning of the left edge of the stencil falls at (2, −1).

A point, say Q on the stencil is at  (4, 1).

Point Q divides the stencil into the ratio 1:4.

We are required to find the end of the stencil.

Mathematically, Point Q divides the stencil internally in the ratio 1:4.

For internal division of a line with beginning point (x_1,y_1) and end point (x_2,y_2) in the ratio m:n, we use the formula

Q(x,y)=(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n} )

(x_1,y_1)=(2, -1), (x_2,y_2)=?, Q(x,y)=(4,1), m:n=1:4

Therefore:

(4,1)=(\dfrac{1x_2+4*2}{1+4} ,\dfrac{1y_2+4*-1}{1+4} )\\(4,1)=(\dfrac{x_2+8}{5} ,\dfrac{y_2-4}{5} )\\$Therefore:\\\dfrac{x_2+8}{5}=4\\x_2+8=4X5\\x_2=20-8=12\\$Similarly\\\dfrac{y_2-4}{5}=1\\y_2-4=5\\y_2=4+5=9\\(x_2,y_2)=(12,9)

The correct option is A.

6 0
2 years ago
Read 2 more answers
The distribution of heights of a certain breed of terrier has a mean of 72 centimeters and a standard de- viation of 10 centimet
RSB [31]

Answer:

Pr(X-Y ≤ 44.2) = 0.5593

Step-by-step explanation:

for a certain breed of terrier

Mean(μ) = 72cm

Standard deviation (σ) = 10cm

n = 64

For a certain breed of poodle

Mean(μ) = 28cm

Standard deviation (σ) = 5cm

n = 100

Let X be the random variable for the height of a certain breed of terrier

Let Y be the random variable for the height of a certain breed of poodle

μx - μy = 72 -28

= 44

σx - σy = √(σx^2/nx + σy^2/ny)

= √10^2/64 + 5^2/100

= √100/64 + 25/100

= √ 1.8125

= 1.346

Using normal distribution,

Z= (X-Y- μx-y) / σx-y

Z= (44.2 - 44) / 1.346

Z= 0.2/1.346

Z= 0.1486

From the Z table, Z = 0.149 = 0.0593

Φ(z) = 0 0593

The probability that the difference of the observed sample mean is at most 44.3 is Pr(Z ≤ 44.2)

Recall that if Z is positive,

Pr(Z≤a) = 0.5 + Φ(z)

Pr(Z ≤ 44.2) = 0.5 + 0.0593

= 0.5593

Therefore,

Pr(X-Y ≤ 44.2) = 0.5593

5 0
2 years ago
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