Answer: no Tony is not correct It is less than 5 hundred dollars.
Step-by-step explanation: 8×37=296 +200 = 496
the upper bound for the length is
.
<u>Step-by-step explanation:</u>
Lower and Upper Bounds
- The lower bound is the smallest value that will round up to the approximate value.
- The upper bound is the smallest value that will round up to the next approximate value.
Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.
Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:
As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :
⇒ 
21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is
.
Answer:
m+7
Step-by-step explanation:
If she ran 7 minutes longer and m represents the amount of time she ran, then it would just be addition.
Let's say m=60 minutes. She would've ran for 67 minutes, which is also m+7.
Answer:
(A)(12, 9)
Step-by-step explanation:
Given:
The beginning of the left edge of the stencil falls at (2, −1).
A point, say Q on the stencil is at (4, 1).
Point Q divides the stencil into the ratio 1:4.
We are required to find the end of the stencil.
Mathematically, Point Q divides the stencil internally in the ratio 1:4.
For internal division of a line with beginning point
and end point
in the ratio m:n, we use the formula

,
, Q(x,y)=(4,1), m:n=1:4
Therefore:

The correct option is A.
Answer:
Pr(X-Y ≤ 44.2) = 0.5593
Step-by-step explanation:
for a certain breed of terrier
Mean(μ) = 72cm
Standard deviation (σ) = 10cm
n = 64
For a certain breed of poodle
Mean(μ) = 28cm
Standard deviation (σ) = 5cm
n = 100
Let X be the random variable for the height of a certain breed of terrier
Let Y be the random variable for the height of a certain breed of poodle
μx - μy = 72 -28
= 44
σx - σy = √(σx^2/nx + σy^2/ny)
= √10^2/64 + 5^2/100
= √100/64 + 25/100
= √ 1.8125
= 1.346
Using normal distribution,
Z= (X-Y- μx-y) / σx-y
Z= (44.2 - 44) / 1.346
Z= 0.2/1.346
Z= 0.1486
From the Z table, Z = 0.149 = 0.0593
Φ(z) = 0 0593
The probability that the difference of the observed sample mean is at most 44.3 is Pr(Z ≤ 44.2)
Recall that if Z is positive,
Pr(Z≤a) = 0.5 + Φ(z)
Pr(Z ≤ 44.2) = 0.5 + 0.0593
= 0.5593
Therefore,
Pr(X-Y ≤ 44.2) = 0.5593