Within the United States, approximately 11.25% of the population is left-handed. Of the males, 12.6% are left-handed, compared t
1 answer:
Answer:
There is a 45.05% probability that the selected person is a right-handed female.
Step-by-step explanation:
We have these following probabilities
A 50% probability that a person is a male
A 50% probability that a person is a female.
A 12.6% probability that a male is left-handed.
A 9.9% probability that a female is left-handed.
If a person is selected at random, to find the probability that the selected person is a right-handed female, one would compute:
50% are female.
9.9% of the females are left-handed, so 100-9.9 = 90.1% of the females are right handed.
So
There is a 45.05% probability that the selected person is a right-handed female.
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The Given Sequence is an Arithmetic Sequence with First term = -19
⇒ a = -19
Second term is -13
We know that Common difference is Difference of second term and first term.
⇒ Common Difference (d) = -13 + 19 = 6
We know that Sum of n terms is given by :
Given n = 63 and we found a = -19 and d = 6
The Sum of First 63 terms is 10521
Answer:
For the critical value we need to calculate the degrees of freedom given by:
And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:
Step-by-step explanation:
Previous concepts
A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.
Let put some notation
x=test value with right arm , y = test value with left arm
The system of hypothesis for this case are:
Null hypothesis:
Alternative hypothesis:
The first step is calculate the difference
The second step is calculate the mean difference
The third step would be calculate the standard deviation for the differences, and we got:
The 4 step is calculate the statistic given by :
For the critical value we need to calculate the degrees of freedom given by:
And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got: