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2 years ago

As a sodium atom is oxidized the number of protons in its nucleus

Chemistry

1 answer:

lara31 [8.8K]2 years ago

6 0

Answer:

The proton remains the same.

Explanation:

Oxidation is simply defined as the loss of electron(s) during a chemical reaction either by an atom, molecule or ion.

Oxidation is strictly on the transfer of electron(s) and not proton.

A metal that undergoes oxidation still has its protons intact otherwise it will not be called the ion of the metal since atomic number is called the proton number.

Sodium (Na) undergoes oxidation as follow:

Na —> Na+ + e-

Na is called sodium metal.

Na+ is called sodium ion.

Na has 11 electrons and 11 protons

Na+ has 10 electrons and 11 protons

From the above illustration, we can see that the protons of Na and Na+ are the same why their electrons differ because Na+ indicates that 1 electron has been loss or transferred.

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Mandarinka [93]

Displaced volume :

Final volume - Initial volume

13.45 mL - 12.00 mL => 1.45 mL

Mass = 4.50 g

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2 years ago

Which is stronger, the strong force (SF) or the electromagnetic force (EMF)? Describe how they battle each other in the nucleus.

Roman55 [17]

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Explanation:

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2 years ago

Explain why you hear a “whoosh” sound when you open a can containing a carbonated drink. Which gas law applies?

Lana71 [14]

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2 years ago

Read 2 more answers

When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at

STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

$1.22 * 10^{5} = - 8.314* 2400 * ln K$

$\\ 1.22 * 10^{5} = -19953.6 * ln K$

$ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022$

So, the equilibrium constant is 0.0022.

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2 years ago