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IrinaK [193]
2 years ago
14

You are performing a simple distillation of roughly 50:50 liquid solution containing two components, hexane and nonane You place

15 ml of the mixture in a round bottom flask, and then collect the distillate sequentially as four three ml samples labeled S1, S2, S3, and S4. Pure hexane has a refractive index of 1.375 and pure nonane has a refractive index of 1.407. You measure a refractive index of 1.385 for one of the four samples. Assuming the refractive index varies linearly with mole fraction, estimate the mole fraction of hexane in this sample.
Chemistry
1 answer:
kifflom [539]2 years ago
6 0

Answer:

Explanation:

Refractive index is a undimensional measurement that describes how fast light travels through the material. It is used to see the liquid purity of compounds.

In this problem you have in the beginning a 50:50 solution oh hexane:nonane and realize distillation.

In distillation the collect is enriched with the most volatille substance (hexane). So you will have in the final sample more hexane than nonane.

Assuming the refractive index varies linearly with mole fraction, you will have:

1,375 → 100% hexane

1,407 → 100% nonane

1,385 → ???

molar fraction of hexane:

100 - (1,385 - 1,375) / (1,407 - 1,375) × 100 = 69 %

molar fraction of nonane:

100 - (1,407 - 1,385) / (1,407 - 1,375) × 100 = 31 %

The relation of the distillating fraction is (69:31) of (hexane:nonane)

You can see that distillation is a technique that allows the separation of a liquid mixture, for example.

I hope it helps!

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Dmitry [639]

Answer:

0.1 M

Explanation:

The overall balanced reaction equation for the process is;

IO3^- (aq)+ 6H^+(aq) + 6S2O3^2-(aq) → I-(aq) + 3S4O6^2-(aq) + 3H2O(l)

Generally, we must note that;

1 mol of IO3^- require 6 moles of S2O3^2-

Thus;

n (iodate) = n(thiosulfate)/6

C(iodate) x V(iodate) = C(thiosulfate) x V(thiosulfate)/6

Concentration of iodate C(iodate)= 0.0100 M

Volume of iodate= V(iodate)= 26.34 ml

Concentration of thiosulphate= C(thiosulfate)= the unknown

Volume of thiosulphate=V(thiosulfate)= 15.51 ml

Hence;

C(iodate) x V(iodate) × 6/V(thiosulfate) = C(thiosulfate)

0.0100 M × 26.34 ml × 6/15.51 ml = 0.1 M

5 0
2 years ago
What is the concentration of a solution made with 0.150 moles of KOH in 400.0 mL of solution?
otez555 [7]

Answer:

concentration = \frac{0.15}{0.4}=0.375 mol/L

Explanation:

Concentration: i is defined as the mole per litre.

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volume=400 ml=0.4 litre

concentration = \frac{0.15}{0.4}=0.375 mol/L

6 0
2 years ago
Write an equation for the formation of bf3(g) from its elements in their standard states.
blagie [28]
In nature, boron is monoatomic. Therefore, its formula is B.
On the other hand, fluorine is diatomic. Therefore, its formula is F2

Now, the basic unbalanced equation is:
B + F2 .........> BF3

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7 0
2 years ago
A 20.0 -\,L volume of an ideal gas in a cylinder with a piston is at a pressure of 3.2 atm. Enough weight is suddenly removed fr
zzz [600]

Answer:

1. ΔE = 0 J

2. ΔH = 0 J

3. q = 3.2 × 10³ J

4. w = -3.2 × 10³ J

Explanation:

The change in the internal energy (ΔE) and the change in the enthalpy (ΔH) are functions of the temperature. If the temperature is constant, ΔE = 0 and ΔH = 0.

The gas initially occupies a volume V₁ = 20.0 L at P₁ = 3.2 atm. When the pressure changes to P₂ = 1.6 atm, we can find the volume V₂ using Boyle's law.

P₁ × V₁ = P₂ × V₂

3.2 atm × 20.0 L = 1.6 atm × V₂

V₂ = 40 L

The work (w) can be calculated using the following expression.

w = - P . ΔV

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The change in the internal energy is:

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6 0
2 years ago
Which solution contains the largest number of moles of chloride ions?
elixir [45]
Molarity = number of moles of solute/liters of solution
number of moles of solute = molarity x liters of solution

Part (a): <span>30.00 ml of 0.100m Cacl2
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Part (b): </span><span>10.0 ml of 0.500m bacl2
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Part (c): </span><span>4.00 ml of 1.000m nacl
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Part (d): </span><span>7.50 ml of 0.500m fecl3
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Based on the above calculations, the correct answer is (d)</span>
5 0
2 years ago
Read 2 more answers
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