Answer:
1 . Closure
2. Distributive
3. Closure
Step-by-step explanation:
Here, we want to know the type of property exhibited or displayed by each of the equations in the question.
Equation 1 displays the closure property.
What this means that if we make an addition operation either way, we would get same answer. So we say that addition is closed for that equation.
Equation 3 exhibits closure property as well. If we go either way on the addition operation for that equation, we are bound to get the same answer.
Equation 2 exhibits the distributive property.
Each term in the bracket is multiplied by the subtraction symbol before we proceeded to complete the arithmetic operations
Answer:
416.67 dollars
Step-by-step explanation:
the exchange rate between U.S. dollar and euro is given as
Exchange rate = 1:0.6
1 U.S. dollar /1 euro = 0.6
cross-multiplying both side
1 x 1 U.S. dollar = 0.6 x 1 euro
1 U.S. dollar = 0.6 euro
multiplying both side by 10
10 U.S. dollar = 0.6 x 10 euro
10 U.S. dollar = 6 euro
dividing both side by "6"
10 U.S. dollar/6 = 6 euro/6
(10/6) U.S. dollar = 1 euro
1 euro = (10/6) U.S. dollar
the ring was bought for 250 euros , we need to convert 250 euros in dollars.
multiplying both side by 250
250 x 1 euro = (250 x 10/6) U.S. dollar
250 euro = 416.67 U.S. dollar
so liza should pay 416.67 U.S. dollar to marie.
Answer:
Variance = 5
Standard deviation = 2.236
0.2650257
Step-by-step explanation:
For a Poisson distribution is σ² = μ.
Given that:
Mean , μ of bankruptcies files per hour = 5
μ = 5
For a Poisson distribution :
P(x = x) = (μ^x * e^-μ) / x!
The Variance and standard deviation :
Variance : σ² = μ = 5
Standard deviation = sqrt(variance) = sqrt(5) = 2.236
B.) Find the probability that at most three businesses will file bankruptcy in any given hour.
P( x ≤ 3) = P(0) + P(1) + P(2) + P(3)
P(x = 0) = (5^0 * e^-5) / 0! = 0.0067379
P(x = 1) = (5^1 * e^-5) / 1! = 0.0336897
P(x = 2) = (5^2 * e^-5) / 2! = 0.0842243
P(x = 3) = (5^3 * e^-5) / 3! = 0.1403738
0.0067379 + 0.0336897 + 0.0842243 + 0.1403738
= 0.2650257
Let <span>Jacob, Carol, Geraldo, Meg, Earvin, Dora, Adam, and Sally be represented by the letters J, C, G, M, E, D, A, and S respectively. </span>
<span>In part IV we are asked:
</span><span>What is the sample space of the pairs of potential clients that could be chosen?
</span><span>
Since the Sample Space is the set of all possible outcomes, we need to make a set (a list) of all the possible pairs, which are as follows:
{(J, C), (J, G), (J, M), (J, E), (J, D), (J, A), (J, S)
, </span>(C, G), (C, M), (C, E), (C, D), (C, A), (C, S)
<span>
</span> , (G, M), (G, E), (G, D), (G, A), (G, S)
<span>
,</span>(M, E), (M, D), (M, A), (M, S)
<span>
, </span>(E, D), (E, A), (E, S) <span>
, </span>(D, A), (D, S)
, (A, S).}
We can check that the number of the elements of the sample space, n(S) is
1+2+3+4+5+6+7=28.
This gives us the answer to the first question: <span>How many pairs of potential clients can be randomly chosen from the pool of eight candidates?
(Answer: 28.)
II) </span><span>What is the probability of any particular pair being chosen?
</span>
The probability of a particular pair to be picked is 1/28, as there is only one way of choosing a particular pair, out of 28 possible pairs.
III) <span>What is the probability that the pair chosen is Jacob and Meg or Geraldo and Sally?
The probability of choosing (J, M) or (G, S) is 2 out of 28, that is 1/14.
Answers:
I) 28
II) 1/28</span>≈0.0357
III) 1/14≈0.0714
IV)
{(J, C), (J, G), (J, M), (J, E), (J, D), (J, A), (J, S)
, (C, G), (C, M), (C, E), (C, D), (C, A), (C, S)
, (G, M), (G, E), (G, D), (G, A), (G, S)
,(M, E), (M, D), (M, A), (M, S)
, (E, D), (E, A), (E, S)
, (D, A), (D, S)
, (A, S).}
