Ask question

Ask question

All categories

2 years ago

13

Laura placed a bucket of water in her garden. Over the course of a week, she watched the water evaporate and recorded the volume

of water left in the bucket each day.
Laura found the linear model that best fit the data was V=5.00−0.25n, where n is the number of days since she first placed the bucket and V is the volume of water, in liters, remaining in the bucket.

How many liters of water evaporated from the bucket every day?
How may liters where inside the bucket when Laura first placed it in the garden?

1 answer:

nikdorinn [45]2 years ago

4 0

Answer:

1. 0.5 L; 2. 5.00 L

Step-by-step explanation:

V = 5.00 - 0.5n

If you include units, the equation becomes

V(in litres) = 5.00 L - (0.5 L/day) × (n days)

1. Rate of evaporation

When you include the units, it becomes easier to see that the water is evaporating at a rate of 0.5 L/day.

That is, 0.5 L of water evaporates each day.

The negative sign shows that the volume of water is decreasing.

2. Volume at the beginning

At the beginning of the experiment, n = 0. Then

V = 5.00 -0.5×0 = 5.00 - 0 = 5.00 L

The bucket originally contained 5.00 L of water.

You might be interested in

Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the br

olga2289 [7]

Since F=m•a, you want to show that a = -5.5

5 0

2 years ago

Read 2 more answers

Stella wants to build up her emergency fund to $10,000. She has $2,000 now and plans on saving $320 every month. To model the si

MA_775_DIABLO [31]

Answer:

Anwers are top to bottom:

1. y − 2,000 = 2,000 + 320x − 2,000

2. division property of equality

3. Y - 2000/320 = X

4. 10,000 - 2,000/360 = 25 = x

Step-by-step explanation:

7 0

2 years ago

Use lagrange multipliers to find the points on the given surface that are closest to the origin. y2 = 64 + xz

Inessa [10]

The distance between an arbitrary point on the surface and the origin is

$d(x,y,z)=\sqrt{x^2+y^2+z^2}$

Recall that for differentiable functions $g(x)$ and $h(x)$ , the composition $g(h(x))$ attains extrema at the same points that $h(x)$ does, so we can consider an augmented distance function

$D(x,y,z)=x^2+y^2+z^2$

The Lagrangian would then be

$L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(y^2-64-xz)$

We have partial derivatives

$\begin{cases}L_x=2x-\lambda z\\L_y=2y+2y\lambda\\L_z=2z-\lambda x\\L_\lambda=y^2-64-xz\end{cases}$

Set each partial derivative to 0 and solve the system to find the critical points.

From the second equation it follows that either $y=0$ or $\lambda=-1$ . In the first case we arrive at a contradiction (I'll leave establishing that to you). If $\lambda=-1$ , then we have

$\begin{cases}2x+z=0\\2z+x=0\end{cases}\implies x=0,z=0$

This means $y^2=64\implies y=\pm8$

so that the points on the surface closest to the origin are $(0,\pm8,0)$ .

8 0

2 years ago

Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th

larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

$p_v =2*P(z>0.546)=0.585$

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

$\hat p=0.2$ estimated proportion

$p_o=0.16$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>0.546)=0.585$

4 0

2 years ago

The triangles are congruent by the SSS congruence theorem. Which rigid transformation(s) can map MNP onto TSR? Reflection only r

ElenaW [278]

Answer:

the answer here is C) translation, then reflection

Step-by-step explanation:

if you translate point P to point R and then translate across that point they map onto each other

7 0

2 years ago

Read 2 more answers