The Hernandez family budget is shown in the graph.
2 answers:
Answer:
housing, savings, and food
housing, food, and transportation
Explanation:
Given: Family Budget comprises of 23% housing, 21% food, 10% savings, 16% transportation, 12% medical, 13% clothing and 5% emergency fund.
To find: categories that make up more than half of the Hernandez family budget
Solution:
clothing + medical + emergency fund =
clothing + housing + savings =
housing + savings + food =
housing + food + transportation =
food + transportation + emergency fund =
So, 3 categories that make up more than half of the Hernandez family budget are housing, savings, and food, housing, food, and transportation
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Answer:
Work input =283.47 KJ
Explanation:
Given that
T=12°C=285 K
m= 2.5 kg
Given that this is the constant temperature process.
e know that work for isothermal process
So now putting the values
W=-283.47 KJ
Negative sign indicates that work is done on the system.
So work input =283.47 KJ
Answer:
hello your question lacks the required figures here is the complete question
A 1.25-in diameter shaft contains a 0.25-in deep U-shaped groove that has a 1/8-in radius at the bottom of the groove. The maximum shear stress in the shaft must be limited to 12000 psi . If the shaft rotates at a constant angular speed of 6Hz , determine the maximum power that may be delivered by the shaft.
Answer: max power delivered by shaft = 4.045 hp
Explanation:
Determine The maximum power that can be delivered by the shaft
using the given data
diameter of shaft ( D ) = 1.25 inches
depth of U-shaped groove = 0.25 inches
radius of U-shaped groove = 1/8 inches = 0.125 inches
maximum shear stress in shaft = 12000 psi
shaft angular speed at frequency of 6 Hz
firstly calculate
The minor diameter (d) = 1.25 - 2(0.25 ) = 0.5 inches
Ratio = radius of groove / minor diameter = 0.125 / 0.75 = 0.167
Ratio, = diameter of shaft / minor diameter = 1.25 / 0.75 = 1.667
k = 1.39 from stress concentration factors graph
calculate the maximum shear stress produced by the torque in the minor diameter of the shaft
<em>Tmax</em> = -----------equation 1
where Tc = 16T
J =
equation 1 becomes( Tmax ) =
also <em>Tmax</em> = K * <em>Tmin -------- equation 2</em>
<em> </em> 1.39 *
T ≤ 715.122 Ib-in
Tmax = 59.593 Ib-ft ( max shear stress )
Finally calculate the max power transmitted by the shaft
P max = 2fTmax = 2
* 6 * 59.593
therefore Pmax = 2246.6 Ib-ft/s
= 4.045 hp
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