Answer:
X_cp = c/2
Explanation:
We are given;
Chord = c
Angle of attack = α
p u (s) = c 1
p1(s)=c2,
and c2 > c1
First of all, we need to find the resultant normal force on the plate and the total moment about leading edge.
I've attached the solution
Answer:
Explanation:
FromTable A - 20; the values of yield strength and tensile strength are derived by using the "Deterministic ASTM Minimum Tensile and yield strength for some Hot-Rolled (HR) and Cold - Drawn (CD) steels for cold drawn AISI 1020 sheet steel:
We calculate the ratio of the radius in relation to the thickness of the spherical vessel by using the formula:
Since the fraction from the ration is higher than 1°, then the shell can be regarded to be a thin spherical shell.
From here; we estimate the tensile stress induced by using the formula:
Therefore; the tensile stress is equal to the stress-induced in the transverse direction; i.e.
Thus, since
Then the radial stress
By the application of Von Mises Stress; the resultant stress can be estimated as follows:
Then: by relating the Von Mises stress at yield condition:
P = 0.934 kpsi
P = 934 psi
Hence, the pressure at the yield condition is 934 psi
Similarly, relating Von Mises stress at the rupture condition
68 = 61 P
P = 1.11 kpsi
Hence, the pressure at rupture condition is 1.11 kpsi