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Lelu [443]
2 years ago
5

Which of the following is NOT a characteristic of hazardous waste

Engineering
1 answer:
lbvjy [14]2 years ago
8 0

Answer:

A RCRA characteristic hazardous waste is a solid waste that exhibits at least one of four characteristics defined in 40 CFR Part 261 subpart C — ignitability (D001), corrosivity (D002), reactivity (D003), and toxicity (D004 - D043). combustible, or have a flash point less than 60 °C (140 °F).

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The Hamming encoder/decoder in the lecture detected and corrected one error bit. By adding a thirteen bit which is the exclusive
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Cos of error of special characters

The solution has been attached to the portal

7 0
2 years ago
Compute the mass fractions of α ferrite and cementite in pearlite. Assume T=726⁢ C∘.
kotykmax [81]

Answer:

The mass composition of ∝ ferrite is 88.94%.

The mass composition of cementite is 11.05%.

Explanation:

Given that

T=726 °C

We have to find the mass fractions of ferrite nad cementite in pearlite.

Lets take data from ideal Iron -carbon diagram at 726 °C

Composition of ∝ ferrite=0.022 5

Composition of pearlite =0.76 %

Composition of cementite =7.6%

We know that if we want to find the mass fraction the  we use Lever rule .So now by using lever rule

The\ mass\ composition\ of\alpha \ ferrite =\dfrac{6.7-0.76}{6.7-0.022}

So the mass composition of ∝ ferrite is 88.94%.

The\ mass\ composition\ of\ cementite =\dfrac{0.76-0.022}{6.7-0.022}

So the mass composition of cementite is 11.05%.

4 0
2 years ago
A thin, flat plate that is 0.2 m × 0.2 m on a side is oriented parallel to an atmospheric airstream having a velocity of 40 m/s.
Leto [7]

Answer:

The rate of heat transfer from both sides of the plate to the air is 240 W

Explanation:

Given;

area of the flat plate = 0.2 m × 0.2 m = 0.04 m²

velocity of atmospheric air stream, v = 40 m/s

drag force, F =  0.075 N

The rate of heat transfer from both sides of the plate to the air:

q = 2 [h'(A)(Ts -T∞)]

where;

h' is heat transfer coefficient obtained from Chilton-Colburn analogy

h' = \frac{C_f}{2} \rho u C_p P_r^{-2/3}\\\\\frac{C_f}{2} = \frac{\tau'_s}{2*\rho u^2/2}

Properties of air at 70°C and 1 atm:

ρ = 1.018 kg/m³, cp = 1009 J/kg.K, Pr = 0.7, v = 20.22 x 10⁻⁶ m²/s

\frac{C_f}{2} = \frac{(0.075/2)/(0.2)^2}{2*(1.018)(40)^2/2} = 5.756*10^{-4}\\\\Thus,\\h' = 5.756*10^{-4} (1.018*40*1009)*(0.7)^{-2/3}\\\\h' = 30 \ W/m^2.K

Finally;

q = 2 [ 30(0.04)(120 - 20) ]

q = 240 W

Therefore, the rate of heat transfer from both sides of the plate to the air is 240 W

4 0
2 years ago
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When comparing solids to fluids, the following is true: for elastic solids, the stress must be normal. For Newtonian fluids, the
Nat2105 [25]

Answer: D

Find the answer in the explanation

Explanation:

Elastic solid will obey Hooke's law which state that the force applied is proportional to the extension provided the elastic limit is not exceeded.

Examples of Newtonian fluid are water, glycerol, honey and all organic solvents

When comparing solids to fluids, the below statement is true

We can therefore conclude that

For elastic solids, stress is linearly related to strain, and for Newtonian fluids, stress is linearly related to strain rate

4 0
2 years ago
The uniform 8–ft board is pushed down into the water so it makes an angle of θ = 30o with the water surface. If the cross sectio
lana66690 [7]

Answer:

The vertical force, F = 19.9 lb.

Explanation:

3 0
2 years ago
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