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ZanzabumX [31]
2 years ago
9

A rectangular channel 3.0 m wide has a flow rate of 5.0 m3/s with a normal depth of 0.50 m. The flow then encounters a dam that

rises 0.25 m above the channel bottom. Will a hydraulic jump occur?
Engineering
1 answer:
Lina20 [59]2 years ago
8 0

Answer:

The hydraulic will jump since the flow is subcritical ( i.e. Y2 > Yc )

Explanation:

width of channel = 3.0 m

Flow rate = 5 m^3/s

Normal depth = 0.50 m

Flow encounters a dam rise of 0.25 m

To know if the hydraulic jump will occur

we will Determine the new normal depth

Y2 = 3.77m

Yc ( critical depth )= 0.66m

Attached below is the detailed solution

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Compute the mass fractions of α ferrite and cementite in pearlite. Assume T=726⁢ C∘.
kotykmax [81]

Answer:

The mass composition of ∝ ferrite is 88.94%.

The mass composition of cementite is 11.05%.

Explanation:

Given that

T=726 °C

We have to find the mass fractions of ferrite nad cementite in pearlite.

Lets take data from ideal Iron -carbon diagram at 726 °C

Composition of ∝ ferrite=0.022 5

Composition of pearlite =0.76 %

Composition of cementite =7.6%

We know that if we want to find the mass fraction the  we use Lever rule .So now by using lever rule

The\ mass\ composition\ of\alpha \ ferrite =\dfrac{6.7-0.76}{6.7-0.022}

So the mass composition of ∝ ferrite is 88.94%.

The\ mass\ composition\ of\ cementite =\dfrac{0.76-0.022}{6.7-0.022}

So the mass composition of cementite is 11.05%.

4 0
2 years ago
Consider a steady developing laminar flow of water in a constant-diameter horizontal discharge pipe attached to a tank. The flui
dalvyx [7]

Answer:

hello attached is the free body diagram of the missing figure

Fr = \frac{\pi }{4} D^2 [ ( P1 - P2) - pV^2 ]

Explanation:

Average velocity is constant i.e V1 = V2 = V

The momentum equation for the flow in the Z - direction can be expressed as

-Fr + P1 Ac - P2 Ac = mB2V2 - mB1V1 ------- equation 1

Fr = horizontal force on the bolts

P1 = pressure of fluid at entrance

V1 = velocity of fluid at entrance

Ac = cross section area of the pipe

P2 and V2 = pressure and velocity of fluid at some distance

m = mass flow rate of fluid

B1 = momentum flux at entrance , B2 = momentum flux correction factor

Note; average velocity is constant hence substitute V for V1 and V2

equation 1 becomes

Fr = ( P1 - P2 ) Ac + mV ( 1 - 2 )

Fr = ( P1 - P2 ) Ac - mV ---------------- equation 2

equation for mass flow rate

m = <em>p</em>AcV  

<em>p</em> = density of the fluid

insert this into equation 2 EQUATION 2 BECOMES

Fr = ( P1 - P2) Ac - <em>p</em>AcV^2

    = Ac [ (P1 - P2) - pV^2 ]  ---------- equation 3

Note Ac = \frac{\pi }{4} D^2

Equation 3 becomes

Fr = \frac{\pi }{4} D^2 [ (P1 -P2 ) - pV^2 ] ------- relation for the horizontal force acting on the bolts      

6 0
2 years ago
Write multiple if statements: If carYear is before 1967, print "Probably has few safety features." (without quotes). If after 19
Free_Kalibri [48]

Answer:

The solution code is written in Python 3.

  1. carYear = 1995
  2. if(carYear < 1967):
  3.    print("Probably has few safety features.\n")
  4. if(carYear > 1970):
  5.    print("Probably has head rests. \n")
  6. if(carYear > 1991):
  7.    print("Probably has electronic stability control.\n")
  8. if(carYear > 2002):
  9.    print("Probably has airbags. \n")

Explanation:

Firstly, create a variable, <em>carYear</em> to hold the value of year of the car make. (Line 1)

Next, create multiple if statements as required by the question (Line 3-13). The operator "<" denotes "smaller" and therefore <em>carYear < 1967</em> means any year before 1967. On another hand, the operator ">" denotes "bigger" and therefore <em>carYear > 1970 </em>means any year after 1970.

The print statement in each of the if statements is done using the Python built-in function <em>print()</em>. The "\n" is an escape sequence that create a new line at the end of each printed phrase.

5 0
2 years ago
A 60-kg woman holds a 9-kg package as she stands within an elevator which briefly accelerates upward at a rate of g/4. Determine
Anuta_ua [19.1K]

Answer:

force R = 846.11 N

lifting force L = 110.36 N

if cable fail complete both R and L will be zero

Explanation:

given data

mass woman mw = 60 kg

mass package mp = 9 kg

accelerates rate a = g/4

to find out

force R and lifting force L and if cable fail than what values would R and L acquire

solution

we calculate here first reaction R force

we know elevator which accelerates upward

so now by direction of motion , balance the force that is express as

R - ( mw + mp ) × g = ( mw + mp ) × a

here put all these value and a = g/4 and use g = 9.81 m/s²

R - ( 60 + 9 ) × 9.81 = ( 60 + 9  ) × g/4

R = ( 69  ) × 9.81/4  + ( 69 ) 9.81

R = 69  ( 9.81 + 2.4525 )

force R = 846.11 N

and

lifting force is express as here

lifting force = mp ( g + a)

put here value

lifting force = 9 ( 9.81 + 9.81/4)

lifting force L = 110.36 N

and

we know if cable completely fail than body move free fall and experience no force

so both R and L will be zero

5 0
2 years ago
referring to either the CMS file or code book index, what is the cross reference for reduction of a dislocation?
Oksi-84 [34.3K]

Answer:

reposition

Explanation:

if you go to your icd 10 pcs index located on page 1 then  look up reduction the subterm is of a dislocation which leads you to the answer reposition

4 0
2 years ago
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