Answer:

Explanation:
Let assume that heating process occurs at constant pressure, the phenomenon is modelled by the use of the First Law of Thermodynamics:

The specific enthalpies are:
Liquid-Vapor Mixture:

Saturated Vapor:

The thermal energy per unit mass required to heat the steam is:


Answer:
Ψ = 10(y^2) + c
<em><u>y = 1.067m</u></em>
Explanation:
since the flow is one dimensional in positive X direction, the only velocity component is in X, which is denoted by u
while u is a function of y
we find the u in terms of y; u varies linearly wih y
we use similiraty to find the relation
32/1.6 =<em>u/y</em>
<em><u>u = 20y</u></em>
<em><u>Ψ = ∫20ydy</u></em>
<em><u>Ψ = 10(y^2) + c</u></em>
<em><u>(b)</u></em>
<em><u>the flow is half below y = 1.6*(2/3)=1.067 m</u></em>
<em><u>this is because at two third of the height of a triangle lies the centroid of triangle. since the velocity profile forms a right angled triangle , its height is 1.6 m . the flow is halved at y = 1.067m</u></em>
Answer:
25 -
mm
Explanation:
Given data
steel tube : outer diameter = 50-mm
power transmitted = 100 KW
frequency(f) = 34 Hz
shearing stress ≤ 60 MPa
Determine tube thickness
firstly we calculate the ; power, angular velocity and torque of the tube
power = T(torque) * w (angular velocity)
angular velocity ( w ) = 2
f = 2 *
* 34 = 213.71
Torque (T) = power / angular velocity = 100000 / 213.71 = 467.92 N.m/s
next we calculate the inner diameter using the relation
= 467.92 / (60 * 10^6) = 7.8 * 10^-6 m^3
also
c2 = (50/2) = 25 mm
=
= ![\frac{\pi }{0.050} [ ( 0.025^{4} - c^{4} _{1} ) ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B0.050%7D%20%5B%20%28%200.025%5E%7B4%7D%20-%20c%5E%7B4%7D%20_%7B1%7D%20%20%29%20%5D)
therefore; 0.025^4 -
= 0.050 /
(7.8 *10^-6)
= 39.06 * 10 ^-8 - ( 1.59*10^-2 * 7.8*10^-6)
39.06 * 10^-8 - 12.402 * 10^-8 =26.66 *10^-8
=
THE TUBE THICKNESS
= 25 -
mm
Answer: drive
Explanation:
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