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Studentka2010 [4]

2 years ago

10

Patricia can buy individual songs for $1.00 to download. Also, an entire album costs $10.00 to download. She can spend no more t

han a total of $80. She wants to buy no more than four albums, and at least 30 individual songs. The following system of inequalities represents this situation, where x is the number of individual songs and y is the number of albums.

1 answer:

schepotkina [342]2 years ago

6 0

Answer:

The system of inequalities is:

$x\geq30\\\\y\leq4\\\\10x+1y\leq80$

Step-by-step explanation:

We will write each of the conditions stated in this problem

Patricia wants to buy at least 30 individual songs.

$x\geq30$

She wants to buy 4 albums at most.

$y\leq4$

The total expenditure has to be equal or less than $80, when each album cost $10 and each individual song cost $1.

$10x+1y\leq80$

The system of inequalities is:

$x\geq30\\\\y\leq4\\\\10x+1y\leq80$

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The chart below shows one store’s sales of computers, listed by model. 2 circle graphs. A circle graph titled May. Poreg, 262; Q

Brrunno [24]

Answer:

b. 98

Step-by-step explanation:

May and June:

May: 223 Dinztop sales

June: 148 Dinztop sales.

So

$p = \frac{148}{223} = 0.6637$

In June, it sold 0.6637 = 66.37% the amount of computers sold in May.

How many Dinztop computers will be sold in July?

Because of the same percent rate, 0.6637 = 66.37% of the amoutns sold in June.

0.6637*148 = 98

The correct answer is given by option b.

8 0

2 years ago

Read 2 more answers

Katie draws 14 pictures in 24 minutes. At this rate, how many pictures can she draw in 312 minutes?

spin [16.1K]

Answer:

Hi there! the answer should be: Katie can draw 182 pictures in 312 minutes

Step-by-step explanation:

312 ÷ 24 = 13

14 x 13 = 182

hope this helped qwq

5 0

1 year ago

Read 2 more answers

A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.

BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to $160\ ft^{2}$

Part b) The volume is equal to $240\ ft^{3}$

Part c) The volume water left in the trough will be $84\ ft^{3}$

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

$A=2[12*5]=120\ ft^{2}$

<em>Find the area of two trapezoids</em>

$A=2[\frac{1}{2}(8+2)h]$

Applying Pythagoras theorem calculate the height h

$h^{2}=5^{2}-3^{2}$

$h^{2}=16$

$h=4\ ft$

substitute the value of h to find the area

$A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}$

The exterior surface area is equal to

$120\ ft^{2}+40\ ft^{2}=160\ ft^{2}$

Part b) Find the volume

We know that

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=20\ ft^{2}$

$L=12\ ft$

substitute

$V=20(12)=240\ ft^{3}$

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

$A=\frac{1}{2}(5+2)(2)=7\ ft^{2}$

<em>step 2</em>

Find the volume

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=7\ ft^{2}$

$L=12\ ft$

substitute

$V=7(12)=84\ ft^{3}$

4 0

2 years ago

6q + 9 ≤ 9 and 6q + 9 ≥ −9

Ilya [14]

Hello there!

6q + 9 ≤ 9

Start by subtracting 9 from both sides

6q + 9 - 9 ≤ 9 - 9

6q ≤ 0

Then divide both sides by 6

6q/6 ≤ 0/6

q ≤ 0

--------------

The second equation
6q + 9 ≥ -9

Start by subtracting 9 from both sides

6q + 9 - 9 ≥ -9 - 9

6q ≥ -18

Divide both sides by 6

6q/6 ≥ -18/6

q ≥ -3

Good luck with your studies!

7 0

2 years ago

Read 2 more answers

Based on an online poll, 35% of motorists routinely use their cell phone while driving. Tree people are chosen at random from a

mart [117]

Answer:

The anwerss to the question are

(A) P(No less than two people use their phones while driving) = 0.1225

(B) P(The probability that no more than one person of the three people use their cell phone while driving) = 0.147875

Step-by-step explanation:

The given relations are

Percentage of motorists that routinely drive while sing their phone = 35 %

The probaboloty that if a peerson is random;ty selected from a group of hudred person routinely uses their phone wjile friving P(phone) = 35

The probability that a motorist randomly selected fron a set of 100 do not routinely use thir phones while driving = P(No celll phone) = 65

Then the probability that when three people are selected at random at least two people of the three people use their cell phone while driving is

P(phone) = 35/100m = 0.35

P(No celll phone) = 65/100 = 0.65

(A) Probability of at least two of three use their phones whle driving is

0.35×0.35×0.65 +0.35×0.35×0.35 = 0.1225

(B) The probability of only one person out of three seted use their phones while driving is

(0.35)(0.65)(0.65) = 0.147875

7 0

2 years ago